Consider four different processors P1, P2, P3, and P4 executing the same instruction set. P1 has a 3.0 GHz clock rate and a CPI of 1.5; P2 has a 2.5 GHz clock rate and a CPI of 1.25; P3 has a 4.0 GHz clock rate and a CPI of 2.2; P4 has 2.0 GHz clock rate and a CPI of 2.75. a. Assume that processor P2 executes a benchmark program in 10 seconds. Using paper and pencil, calculate the number of cycles required to execute the program and the number of instructions executed in the program. Choose your answers from the following values: 10*10^9; 20*10^9; 18.18*10^9; 30*10^9; 7.27*10^9; 10*10^9; 12.5*10^9; 15*10^9; 32*10^9; 32.5*1019 ; 21.5*1019; 24*10^9; If the calculated answer is not found, write your answer in the same format please. • Cycles (P2)= Blank 1 • No. instructions (P2)= Blank 2 b. We are trying to reduce the execution time by 25%, but this leads to an increase of 20% in the CPI. What is the new CPI for the processor P2? And if P2executes a 20*10^9 instructions program, what clock rate (in GHz) should we have to get this time reduction? Choose your answers from the following values: 1.8 ; 7.04; 2.64; 1.5; 2.4; 4.8; 4.0; 3.3; 6.4; 5.0; 3.5; 4.5; 2.8 ; 4.6; 8.8; 2.25; 3.0. If the calculated answer is not found, write your answer in the same format please. • CPInew (P2)= Blank 3 • Clock rate (P2)= Blank 4 GHz

Systems Architecture
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ISBN:9781305080195
Author:Stephen D. Burd
Publisher:Stephen D. Burd
Chapter4: Processor Technology And Architecture
Section: Chapter Questions
Problem 3PE: Processor R is a 64-bit RISC processor with a 2 GHz clock rate. The average instruction requires one...
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Consider four different processors P1, P2, P3, and P4 executing the same instruction set. P1 has a 3.0 GHz clock rate and a CPI of
1.5; P2 has a 2.5 GHz clock rate and a CPI of 1.25; P3 has a 4.0 GHz clock rate and a CPI of 2.2; P4 has 2.0 GHz clock rate and a CPI
of 2.75.
a. Assume that processor P2 executes a benchmark program in 10 seconds. Using paper and pencil, calculate the number of cycles
required to execute the program and the number of instructions executed in the program. Choose your answers from the
following values: 10*10^9; 20*10^9; 18.18*10^9; 30*10^9; 7.27*10^9; 10*10^9; 12.5*10^9; 15*10^9; 32*10^9; 32.5*10^g
; 21.5*10^9; 24*10^9; If the calculated answer is not found, write your answer in the same format please.
• Cycles (P2)= Blank 1
• No. instructions (P2)= Blank 2
b. We are trying to reduce the execution time by 25%, but this leads to an increase of 20% in the CPI. What is the new CPI for the
processor P2? And if P2executes a 20*10^9 instructions program, what clock rate (in GHz) should we have to get this time
reduction? Choose your answers from the following values: 1.8 ; 7.04; 2.64; 1.5; 2.4; 4.8; 4.0; 3.3; 6.4; 5.0; 3.5; 4.5; 2.8
; 4.6; 8.8; 2.25; 3.0. If the calculated answer is not found, write your answer in the same format please.
• CPlnew (P2)= Blank 3
• Clock rate (P2)= Blank 4 GHz
Transcribed Image Text:Consider four different processors P1, P2, P3, and P4 executing the same instruction set. P1 has a 3.0 GHz clock rate and a CPI of 1.5; P2 has a 2.5 GHz clock rate and a CPI of 1.25; P3 has a 4.0 GHz clock rate and a CPI of 2.2; P4 has 2.0 GHz clock rate and a CPI of 2.75. a. Assume that processor P2 executes a benchmark program in 10 seconds. Using paper and pencil, calculate the number of cycles required to execute the program and the number of instructions executed in the program. Choose your answers from the following values: 10*10^9; 20*10^9; 18.18*10^9; 30*10^9; 7.27*10^9; 10*10^9; 12.5*10^9; 15*10^9; 32*10^9; 32.5*10^g ; 21.5*10^9; 24*10^9; If the calculated answer is not found, write your answer in the same format please. • Cycles (P2)= Blank 1 • No. instructions (P2)= Blank 2 b. We are trying to reduce the execution time by 25%, but this leads to an increase of 20% in the CPI. What is the new CPI for the processor P2? And if P2executes a 20*10^9 instructions program, what clock rate (in GHz) should we have to get this time reduction? Choose your answers from the following values: 1.8 ; 7.04; 2.64; 1.5; 2.4; 4.8; 4.0; 3.3; 6.4; 5.0; 3.5; 4.5; 2.8 ; 4.6; 8.8; 2.25; 3.0. If the calculated answer is not found, write your answer in the same format please. • CPlnew (P2)= Blank 3 • Clock rate (P2)= Blank 4 GHz
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