Determine the new per unit value of the generator impedance base from the given bases. Generator G: 15 MVA, 13.8 kV, X = 0.15 p.u. Motor M1: 5 MVA, 13.8 kV, X = 0.15 p.u. Motor M2: 5 MVA, 14.4 kV, X = 0.15 p.u. T;: 25 MVA, 13.2 – 161 kV, X = 0.1 p.u. T;:15 MVA, 13.8 –. 161 kV, X = 0.1 p.u. Line: j100 N (actual) Select a base of 100 MVA and 161 kV in the transmission line. T T2 Line pu 1.09 pu 0.15 pu 0.91 pu

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter9: Unsymmetrical Faults
Section: Chapter Questions
Problem 9.5P
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Determine the new per unit value of the generator impedance base from the
given bases.
Generator G: 15 MVA, 13.8 kV, X = 0.15 p.u.
Motor M1: 5 MVA, 13.8 kV, X = 0.15 p.u.
Motor M2: 5 MVA, 14.4 kV, X = 0.15 p.u.
T;: 25 MVA, 13.2 – 161 kV, X = 0.1 p.u.
T;:15 MVA, 13.8 –. 161 kV, X = 0.1 p.u.
Line: j100 N (actual)
Select a base of 100 MVA and 161 kV in the transmission line.
T
T2
Line
pu
1.09 pu
0.15 pu
0.91 pu
Transcribed Image Text:Determine the new per unit value of the generator impedance base from the given bases. Generator G: 15 MVA, 13.8 kV, X = 0.15 p.u. Motor M1: 5 MVA, 13.8 kV, X = 0.15 p.u. Motor M2: 5 MVA, 14.4 kV, X = 0.15 p.u. T;: 25 MVA, 13.2 – 161 kV, X = 0.1 p.u. T;:15 MVA, 13.8 –. 161 kV, X = 0.1 p.u. Line: j100 N (actual) Select a base of 100 MVA and 161 kV in the transmission line. T T2 Line pu 1.09 pu 0.15 pu 0.91 pu
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