Experiment 11: ACID-BASE TITRATION Sample Data Collection and Results Pages Volume of NaOH used in the Titration: Rough trial Trial 3 Trial 2 Trial 1 Initial reading (mL) Z1.0SML o.O0mL O.00ML o.00ML Final reading (mL) 43.15 mL 21.oom L Z1.45ML Z1.50mL Volume dispensed (mL) 21.55ML 21.Lo5mL 21.0OmL 21.SOML Average volume of NAOH used (Trials 1-3) 21.oomL O. 2012 M Molarity of NaOH MOLES MOLARITY 11 NA Unknown Vinegar # LITERS

Experiment 11: ACID-BASE TITRATION Sample Data Collection and Results Pages Volume of NaOH used in the Titration: Rough trial Trial 3 Trial 2 Trial 1 Initial reading (mL) Z1.0SML o.O0mL O.00ML o.00ML Final reading (mL) 43.15 mL 21.oom L Z1.45ML Z1.50mL Volume dispensed (mL) 21.55ML 21.Lo5mL 21.0OmL 21.SOML Average volume of NAOH used (Trials 1-3) 21.oomL O. 2012 M Molarity of NaOH MOLES MOLARITY 11 NA Unknown Vinegar # LITERS

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter15: Complex Acid/base Systems

Section: Chapter Questions

Problem 15.29QAP

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In the experiment, we used titration to determine the total acid content ofsamples, which we reported in terms of molarity. Reporting acidity through pHmeasurements is quite different, in that we can only measure the amount of theacid in its ionized form. You were tasked to investigate a clear aqueous solutionof an unknown monoprotic acid. You decided to use two methods togather data.Method 1 – TITRATION: A 10. mL aliquot of the sample was diluted with 25 mLdistilled water. Two drops of phenolphthalein were added and then it was titrated3.54 mL of 0.048 M standardized NaOH to the endpoint.Method 2 – pH STRIP: You took 1 mL of the sample and used a pH strip toestimate the pH, which turned out to be around 3.3. Another 1 mL of the samplewas diluted with 9 mL of water. The pH was taken again and is now around 3.8.a) Calculate the molarity of the acid using the titration data.b) If we assume that the titrated unknown is a strong acid, predict thepH of the sample.c) Using pH strip results,…
20.0 mL of 1:1 buffer 5.00 mL of standard NaOH pKa=4.66 [NaOH]=0.1108M pH=5.19
Please help me fill out this table! Answering just one of the columns is good enough, thank you! Concentration of Standardized NaOH - 1.00 mol/L Mass concentration of acetic acid - 2.40 g/L Trial 1 Trial 2 Measured pH of the acetic acid solution 3.07 3.05 Mass of acetic acid solution taken for titration 20.0 g 20.0 g Initial buret reading of NaOH titrant 0.00 mL 0.00 mL Final buret reading of NaOH titrant 0.82 mL 0.79 mL Net volume of NaOH 0.82 mL 0.79 mL Millimoles of NaOH to end point of titration _?_mmol _____mmol Millimoles of acetic acid in sample _?_mmol ______mmol Molar concentration of acetic acid solution _?_mol/L ______mol/L
Trial 1: Initial pH= 3.92mL Mass of KHP and Paper= 0.868g Mass of paper= 0.357g Mass of KHP= 0.511g Trial 2: Initial pH= 4.09ml Mass of KHP and Paper= 0.870g Mass of paper= 0.359g Mass of KHP= 0.511g 1)Use Kb, the number of moles of C8H4O4^2- at the equivalence point, and the total volume at that point to calculate the pH for each sample at the equivalence point. Compare these calculated results with the experimental results.
Titration of unknown acid with NaOH. Determine the pKa of unknown acid: mass H2A=0.5 g H2O=50 mL Volume @ eq point: 23.7 mL NaOH= 0.2084M pH @ Veq = 7.9 H2A+H2O <---->[HA-]+[H3O+]
concentration of I3- : 0.002M d. Titration data: Final volume: 29.05 mL Starting volume: 38.10 mL Delivered volume: 25.15 mL How do you calculate g?
A multivitamin sample has a label claim of 500 mg ascorbic acid (176.12 g/mol). According to quality assurance guidelines for stability, it has an acceptable range of 90.0%-110.0% of the label claim. After production, the multivitamin was analyzed through acid-base titration, and the sample needed 25.40 mL of a 0.1101 M NaOH titrant to reach the end point. After 3 months, the same multivitamin was analyzed again, and this time 23.34 mL of the same 0.1101 M titrant was used. After 6 months, the same multivitamin was analyzed again, and this time, 22.48 mL of the same 0.1101 M NaOH titrant was needed to reach the end point. If the multivitamin was manufactured on March 2021, when is its most likely expiration date? June 2021 September 2021 December 2021 March 2022
A multivitamin sample has a label claim of 500 mg ascorbic acid (176.12 g/mol). According to quality assurance guidelines for stability, it has an acceptable range of 90.0%-110.0% of the label claim. After production, the multivitamin was analyzed through acid-base titration, and the sample needed 25.40 mL of a 0.1101 M NaOH titrant to reach the end point. After 3 months, the same multivitamin was analyzed again, and this time 23.34 mL of the same 0.1101 M titrant was used. After 6 months, the same multivitamin was analyzed again, and this time, 22.48 mL of the same 0.1101 M NaOH titrant was needed to reach the end point. 1. How many mg of ascorbic acid is present in the sample after production? 2. How many mg of ascorbic acid are present in the 3 month old sample? 3. How many mg of ascorbic acid are present in the 6 month old sample? 4. If the multivitamin was manufactured on March 2021, when is its most likely expiration date? a. June 2021 b. September 2021 c. December 2021…
A multivitamin sample has a label claim of 500 mg ascorbic acid (176.12 g/mol). According to quality assurance guidelines for stability, it has an acceptable range of 90.0%-110.0% of the label claim. After production, the multivitamin was analyzed through acid-base titration, and the sample needed 25.40 mL of a 0.1101 M NaOH titrant to reach the end point. After 3 months, the same multivitamin was analyzed again, and this time 23.34 mL of the same 0.1101 M titrant was used. After 6 months, the same multivitamin was analyzed again, and this time, 22.48 mL of the same 0.1101 M NaOH titrant was needed to reach the end point.
A multivitamin sample has a label claim of 500 mg ascorbic acid (176.12 g/mol). According to quality assurance guidelines for stability, it has an acceptable range of 90.0%-110.0% of the label claim. After production, the multivitamin was analyzed through acid-base titration, and the sample needed 25.40 mL of a 0.1101 M NaOH titrant to reach the end point. After 3 months, the same multivitamin was analyzed again, and this time 23.34 mL of the same 0.1101 M titrant was used. After 6 months, the same multivitamin was analyzed again, and this time, 22.48 mL of the same 0.1101 M NaOH titrant was needed to reach the end point. A. How many mg of ascorbic acid is present in the sample after production? 521.0 mg 506.7 mg 492.53 mg 488.12 m B. How many mg of ascorbic acid are present in the 3 month old sample? 492.53 mg 488.12 mg 452.58 mg 435.91 mg C. How many mg of ascorbic acid are present in the…
Prepared buffer solution GivenAmmonia Volume = 68 mL | Ammonia Concentration = 0.17 MAmmonium Chloride Volume = 42 mL | Ammonium Chloride Concentration = 0.13 MDissociation Constant of Ammonia: 1.8x10-5What is the total vol. of buffer
An automatic titration of Cola product was analyzed and the following results were produced: Volume of Standardized NaOH Titrant used to achieve the first equivalence point in titration: Trial #1: 1.300 mL Trial #2: 1.137 mL Trial #3: 1.140 mL May you explain why trial #1 was skewed; for example, if pipetting of the 25.00 mL was done incorrectly, how would the molarity change if the volume examined was supposed to be 24.50 mL?