he bands indicated by arrow "A" (to the left of the western blot) most likely represent: A. PX-HA lacking any post-translational modifications. B. dephosphorylated PX-HA. C. phosphorylated PX-HA. D. PX-HA with its N-terminal signal sequence still attached. E. glycosylated PX-HA.
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he bands indicated by arrow "A" (to the left of the western blot) most likely represent:
| A. |
PX-HA lacking any post-translational modifications. |
|
| B. |
dephosphorylated PX-HA. |
|
| C. |
phosphorylated PX-HA. |
|
| D. |
PX-HA with its N-terminal signal sequence still attached. |
|
| E. |
glycosylated PX-HA. |
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- There is Hyaluronic acid synthesis occuring in Group X Strep and it is controlled by an operon with 3 genes, called hasXYZ. Based on the 3-line diagram model, a. How many ribosome binding sites are there for the protein? b. How many promoters are there for the genes? c. How many start codons are there for the protein? d. How many RNA Polymerase binding locations are there for the genes? e. How many proteins will be fully functional? f. How many mRNA strands are made?Gene expression in bacteria is controlled by the operon model. a) Why is the operon model important? b) Why is the trp operon known as a repressible operon?. a. How many ribosomes are required (at a minimum)for the translation of trpE and trpC from a singletranscript of the trp operon?b. How would you expect deletion of the two tryptophan codons in the RNA leader to affect theexpression of the trpE and trpC genes?
- What would happen to the regulation of the tryptophan operon in bacterial cells that express a mutant form of the tryptophan repressor that (1) cannot bind to DNA, (2) cannot bind tryptophan, or (3) binds to DNA even in the absence of tryptophan?Many bacterial genes with related functions are arranged in operons, sets of contiguous genes that are under the control of a single promoter and are transcribed together. (a) What is the advantage of this arrangement? (b) How might eukaryotic cells, which do not contain operons, ensure the simultaneous transcription of different genes?Which ONE of the following is TRUE concerning the so‐called Philadelphia chromosome? Select one: A.It results in loss of BCR serine‐threonine kinase activity B.It leads to generation of a fusion protein with constitutively active tyrosine kinase activity C.It results from a t(8;21) translocation D.Overexpression of the ABL1 gene results from a translocation that brings a strong gene promoter close to the ABL1 gene
- A graduate student studying the pathogenic bacteria Acinetobacter baumannii made cDNA from planktonic cells and biofilm cells and performed RNA-Seq on both samples. She aligned her sequencing reads to a locus of the baumannii genome as shown. a. Which genes are on an operon together? Explain which data supports this? b. What is the most expressed transcript from the locus in Planktonic culture? c. Order the transcripts from largest increase in relative expression between biofilm and planktonic cells to the largest decrease in relative expression. d. When this data was compared to microarray transcriptional profiling, the microarray data provided lower expression levels for the most highly expressed transcripts. Why did this occur?You run a Western blot to detect Ras in sampe A and sample B. You find that sample B gives a darker band. What is the most appropriate interpretation of this? (a) sample A has more Ras DNA, (b) sample B has more Ras DNA, (c) sample A has more Ras mRNA, (d) sample B has more Ras mRNA, (e) sample A has more Ras protein, (f) sample B has more Ras protein. I understand that those molecules have higher molecular weight should give darker band. As mRNA has higher molecular weight than that of DNA and protein, I wish to pick (d) "sample B has more Ras mRNA" as the best answer. I am not sure if I am right. Please the expert advise.A mutation that inactivates the repressor gene of the lac operon results in (a) the continuous transcription of the structural genes (b) no transcription of the structural genes (c) the binding of the repressor to the operator (d) no production of RNA polymerase (e) no difference in the rate of transcription
- Analyzing Cloned Sequences A base change (A to T) is the mutational event that created the mutant sickle cell anemia allele of beta globin. This mutation destroys an MstII restriction site normally present in the beta globin gene. This difference between the normal allele and the mutant allele can be detected with Southern blotting. Using a labeled beta globin gene as a probe, what differences would you expect to see for a Southern blot of the normal beta globin gene and the mutant sickle cell gene?INTERPRET DATA Develop a simple hypothesis that would explain the behavior of each of the following types of mutants in E. coli. Mutant a: The map position of this mutation is in the trp operon. The mutant cells are constitutive; that is, they produce all the enzymes coded for by the trp operon, even if large amounts of tryptophan are present in the growth medium. Mutant b: The map position of this mutation is in the trp operon. The mutant cells do not produce any enzymes coded for by the trp operon under any conditions. Mutant c: The map position of this mutation is some distance from the trp operon. The mutant cells are constitutive; that is, they produce all the enzymes coded for by the trp operon, even if the growth medium contains large amounts of tryptophan.In the presence of tryptophan, and a mutation in the allosteric domain that abolishes tryptophan binding______. a) the active repressor cannot bind trp), so operon gene transription is attenuated b) the inactive repressor cannot bind trpO, so operon gene transcription occurs] c) the active repressor binds trpP, so operon gene trasncription is repressed, the inducer cannot bind trpO, so gene transcription occurs d) the repressor binds to the corepressor, and an operon gene transcription occurs
