Shown below is a DNA coding strand: 5' T-A-C-T-T-C-C-C-G-A-T-C-A-T-T 3' Using the genetic code provided, list the amino acid sequence at the end of translation. Show how you got your answer.
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A: b) UUA: Leucine c) GAG: Glutamate d) UAU CUA: Tyrosine-Leucine e) AUC UUG: Isoleucine-Leucine
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Shown below is a DNA coding strand:
5' T-A-C-T-T-C-C-C-G-A-T-C-A-T-T 3'
Using the genetic code provided, list the amino acid sequence at the end of translation. Show how you got your answer.
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- A certain mRNA strand has the following nucleotide sequence: 5AUGACGUAUAACUUU3 What is the anticodon for each codon? What is the amino acid sequence of the polypeptide? (Use Figure 13-5 to help answer this question.) Figure 13-5 The genetic code The genetic code specifies all possible combinations of the three bases that compose codons in mRNA. Of the 64 possible codons, 61 specify amino acids (see Figure 3-17 for an explanation of abbreviations). The codon AUG specifies the amino acid methionine and also signals the ribosome to initiate translation (start). Three codonsUAA, UGA, and UAGdo not specify amino acids; they terminate polypeptide synthesis (stop).The genetic code is defined as a series of _______________ in _______________. (a) anticodons; tRNA (b) codons; DNA (c) anticodons; mRNA (d) codons; mRNA (e) codons and anticodons; rRNAIf the genetic code used 4 bases at a time, how many amino acids could be encoded?
- DNA gene TAC AGC TTT mRNA codon (No thymine in RNA!) tRNA anticodon (No thymine in RNA!) Amino acid Use the mRNA with the Genetic Code. Use the mRNA with the Genetic Code. Answer the questions below. Questions How many nucleotides would be needed to code for a protein that has 100 amino acids? Using the Genetic Code in Table 6.3, write all of the possible codons that signal the start and end of a gene. Start: End: An amino acid sequence of a protein molecule includes methionine, lysine, serine and glycine. Show each different codon that could result in each of these amino acids. You will have more than one codon for all of them except methionine. Amino Acids All Possible Codons Methionine Lysine Serine (Look carefully. There are six possibilities) Glycine Question 3 illustrates the redundant nature of the genetic code. Can you think of an advantage of having several codons that all code for the…Which of the following statements about the translation process is correct? a. RNA is made complimentary to DNA b. A protein is made from the DNA base sequence c. DNA is made complimentary to RNA d. A protein is made from the RNA base sequenceComplete what is being asked and finally with the Genetic Code table, determine what specific amino acids will be finally formed. Given DNA strand 3’ T A C T A G C C T A C T G C G 5’ 1. The partner strand of the given _________________________________ 2. The mRNA strand formed _____________________________________ 3. The tRNA _________________________________________________ 4. The amino acids formed are __________________________________
- Using the codon table, identify a 5’-3’ sequence of nucleotides in the dna template strand for mRna coding for the polypeptide sequence NH2-PHe-Pro-lys-COOH.The following bacterial DNA sequence uses the top strand as the coding strand and the bottom strand as the template strand. Write what the messenger RNA sequence for this gene would be after transcription occurs.how many codons would exist in a genetic code that was four bases long (instead of three)? DRAW and Show your work.
- For the following DNA sequence TAC-CCC-AAA-TTT-ATC Write: the mRNA codons the tRNA anticodons the protein formedfollowing is a series of DNA triplets. first, transcribe the correct complementary sequence of mRNA codons. then, write out the tRNA antcodon that will bind to the mRNA codon during translation. finally, use figure 3.28 in your text to find the amino acid that corresponds with each mRNA codon. TAC TTT TAG CGG AAC GGT TTA CAT ATT mRNA sequence: tRNA anticodons Amino acidsIf given the following coding strand of DNA, what is the mRNA? What tRNA will be present? (hint - draw this!) DNA: A A A C C G A T C C T T A A T G G C T T A mRNA: tRNA: