The total number of cells in a culture is counted using the trypan blue exclusion assay and is found to be 6.8 x 106 cells/ml. Each well in a 6 well plate requires 2 x 105 cells. How should the solution be diluted so that 1ml can be added to each well?
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- In this experiment, a culture was serially diluted to the concentrations below. Each plate was plated with 0.25mL of the dilution. Using the most diluted plate, what is the correct concentration of the original culture? A) 2.0 X 10^-3 cells/mL B) 2.0 X 10^5 cells/mL C) 4.0 X 10^5 cells/mL D) 5.0 X 10^4 cells/mLAt the station there is a 2 mL microcentrifuge tube containing sheep blood and 3 tubes containing the following solutions: 0 mM, 300 mM, 600 mM of sucrose. The tubes are randomly labelled A, B, C. 2 mL of each solution were transferred to a different microcentrifuge tube, 20 ul of blood were then added to each tube, and they were mixed well by inverting the tube for multiple times. They were observed and it was determined whether the solution in each tube was hypotonic (Yes or No) relative to the blood cells. In addition, the solutions were diluted with water to help you determine which solution is which sucrose concentration. What sucrose concentration corresponds with each tube? Tube Hypotonic (Yes/No) Hypotonic after 1:1 dilution with water (Yes/No) Most likely Sucrose concentration (mM) A No Yes B Yes Yes C No NoWhich of the following assays would you use to tell the two cultures apart?
- You aseptically transfer 1ml of your original liquid culture into 999 ml of sterile water. What is the dilution factor?In the ELISA, the pH the coating buffer was 9.6 whereas the pH of the sample buffer (PBS based) was 7.4 a) Why was the pH of the coating buffer so different?b) What is “coating buffer” for an ELISA? Does the buffer molecule usedmake sense based on the desired pH?In an ELISA procedure the samples are incubated and the ELISA plate iscovered with parafilm and placed in a humidified chamber to preventevaporation of the small liquid volumes in the wells.c) How would your results change if you did not incubate in a humidifiedchamber?You are testing unpasteurized milk for the presence of bacterial contamination. Starting from the undiluted milk, you do serial dilutions, and plate 0.5 ml of 4th dilution on agar. If you counted 78 CFUs from the 4th plate, how many bacteria/ml do you expect? (show solution) Do you think standard plate counts are very accurate? Why or why not?
- With a plate count average of 297 and a final dilution on the plate of 1:1,000 ; what is the viable number of cells in original culture (CFU/ml)?What is the color result of 1% solution of casein, Albumin, Gelatin in ninhydrin test? Include picture and interpretation With referenceYou are given a bacterial culture which has a concentration of approximately 5.0 x 10^8 cells/mL. List a series of dilutions and platings that you could carry out in order to determine the exact concentration of the culture. Note that you must plate four plates from a minimum of two dilution tubes. The volumes plated should be in the range of 0.1 mL – 1.0 mL. Duplicate volumes may not be plated from any one dilution tube. Each plating should aim for a count between 30 and 300 CFUs. You can select any value from 30-300 for CFU and any volume from 0.1-1.0 to find out dilution scheme
- Monospot: inconclusive Heterophile antibody titer of 1:56 Differential tests: Guinea pig kidney titer of 1:56 Beef red blood cell titer of 0 How would you interpret the above results? What other confirmatory test can be utilized to resolve doubtful?A serial dilution of overnight E.coli culture was performed by pipetting 1ml of a bacterial culture into a 9 ml LB medium. After this, from 10-4 and 10-5 dilution tubes 100µl were plated onto LB agar plates. Upon overnight incubation at 37°C, 200 colonies were counted in 10-4 and 22 colonies were present on 10-5 plates. How many colony-forming units were present per ml of the original culture? If the formula for CFU/ml =no. Of colonies/dilution factor*volume of culture plateWhich of the following is a reason to run simultaneous tests on known positive and negative controls when identifying an unknown microbe using biochemical tests? The controls maintain the differential qualities of the test medium The controls can show if there was contamination of the tubes with another species The controls will ensure that the unknown microbe multiplies on the medium The controls can show if there was a recent mutation in your unknown microbe