Chapter 10, Problem 10.138MP

Interpretation Introduction

(a)

Interpretation:

The moles of mixture of gases A and B produced from are to be calculated.

Concept introduction:

The formula to calculate number of moles as per ideal gas equation is as follows:

$n=\frac{PV}{RT}$

Where,

• $R$ is gas constant.
• $V$ denotes the volume.
• $n$ denotes number of moles.
• $T$ denotes temperature.
• $P$ denotes pressure.

The conversion factor to convert $\text{atm}$ to $\text{mm Hg}$ is as follows:

$1\text{ atm}=\text{760 mm Hg}$

Interpretation Introduction

(b)

Interpretation:

The moles of gas B produced are to be calculated.

Concept introduction:

The formula to calculate number of moles as per ideal gas equation is as follows:

$n=\frac{PV}{RT}$

Where,

• $R$ is gas constant.
• $V$ denotes the volume.
• $n$ denotes number of moles.
• $T$ denotes temperature.
• $P$ denotes pressure.

The relation between $\text{Pa}$ and $\text{atm}$ is as follows:

$\text{1 atm}=101325\text{ Pa}$

The conversion factor to convert $\text{atm}$ to $\text{mm Hg}$ is as follows:

$1\text{ atm}=\text{760 mm Hg}$

Interpretation Introduction

(c)

Interpretation:

Density of gas B produced is to be calculated.

Concept introduction:

The expression of density is given as follows:

$\text{Density}=\frac{\text{Mass}}{\text{Volume}}$

d)

Interpretation Introduction

Interpretation:

Molecular weight of gas B is to be calculated.

Concept introduction:

The expression to determine molar mass from moles is as follows:

$\text{Molar mass}=\frac{\text{Given Mass}}{\text{Number of moles}}$

Interpretation Introduction

(e)

Interpretation:

Balanced reaction for $\text{Mercuric}\left(\text{I}\right)\text{acetate}$ with ${\text{HNO}}_{\text{3}}$ should be written.

Concept introduction:

The molecular formula of $\text{mercuric}\left(\text{I}\right)\text{acetate}$ is ${\text{Hg}}_2{\text{CO}}_3$. Any chemical equation obeys law of conservation of mass.