Chapter 10.3, Problem 10.12P

Interpretation Introduction

(a)

Interpretation:

The quantity of phosphorus-32 should be calculated which remains from 1.00 g sample after 2 half-lives.

Concept Introduction:

The time which is required for a quantity to reduce to half of its initial value is known as half -life.

Or,

The time at which the reactant concentration is reduced to half of its initial concentration is known as half-life.

The expression for calculating amount left after decay of radioactive atom is shown as:

  $A=A_{orig}{\left(\frac{1}{2}\right)}^t$

Where, t = number of half-lives that passed.

Interpretation Introduction

(b)

Interpretation:

The quantity of phosphorus-32 should be calculated which remains from 1.00 g sample after 4 half-lives.

Concept Introduction:

The time which is required for a quantity to reduce to half of its initial value is known as half -life.

Or,

The time at which the reactant concentration is reduced to half of its initial concentration is known as half-life.

The expression for calculating amount left after decay of radioactive atom is shown as:

  $A=A_{orig}{\left(\frac{1}{2}\right)}^t$

Where, t = number of half-lives that passed.

Interpretation Introduction

(c)

Interpretation:

The quantity of phosphorus-32 should be calculated which remains from 1.00 g sample after 8 half-lives.

Concept Introduction:

The time which is required for a quantity to reduce to half of its initial value is known as half -life.

Or,

The time at which the reactant concentration is reduced to half of its initial concentration is known as half-life.

The expression for calculating amount left after decay of radioactive atom is shown as:

  $A=A_{orig}{\left(\frac{1}{2}\right)}^t$

Where, t = number of half-lives that passed.