Chapter 11.1, Problem 29WE

(a)

To determine

To Find: The total wall area.

Answer to Problem 29WE

  $768f{t}^2$

Explanation of Solution

Given: A room $28ft$ long and $20ft$ wide has wall $8ft$ high.

The dimension of room has four rectangles.

Thus

The area of the room is

  $\begin{array}{l}A=(28\times 8)+(20\times 8)+(28\times 8)+(20\times 8)\\ A=16(28+20)\\ A=768f{t}^2\end{array}$

Hence, area of the wall is $768f{t}^2$

(b)

To determine

To Find: How many gallon cans of paint should be bought to paint the walls if $1$ gal paint covers $300f{t}^2$ .

Answer to Problem 29WE

  $2.56gallon$

Explanation of Solution

Given: A room $28ft$ long and $20ft$ wide has wall $8ft$ high.

Area of the wall is $768f{t}^2$

If $300f{t}^2$ cover = $1gallon$

  $768f{t}^2$ Cover = $\frac{768}{300}=2.56gallon$

Hence, $2.56gallon$ is required.