(a)
To Find: The area of bull eye and each ring of target.
(a)
Answer to Problem 23WE
Explanation of Solution
Given: A target consist of four concentric
Given:
Area of circles with radius
Now the area of the first ring is the difference of area of second circle and bull eye.
Thus
i.e. the area of the first ring is
Now
Area of circles with radius
The area of the second ring is the difference of area of circle with radius three and two.
Area of circle with radius
Area of third ring,
Hence, the area of the rings are
(b)
To Find: The area of
(b)
Answer to Problem 23WE
Explanation of Solution
Given: A target consist of four concentric circles of radius
Area of circle with radius
Area of circle with radius
Now area of
Chapter 11 Solutions
McDougal Littell Jurgensen Geometry: Student Edition Geometry
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- Elementary Geometry For College Students, 7eGeometryISBN:9781337614085Author:Alexander, Daniel C.; Koeberlein, Geralyn M.Publisher:Cengage,Elementary Geometry for College StudentsGeometryISBN:9781285195698Author:Daniel C. Alexander, Geralyn M. KoeberleinPublisher:Cengage Learning