Chapter 11.3, Problem 1CE

To determine

To Find: The area of the trapezoid and length of the median.

Answer to Problem 1CE

  $A=50sq.unit$

  $M=10$

Explanation of Solution

Given:

  

Area of Trapezoid.

  $A=\frac{1}{2}h(b_1+b_2)$

Here

  $\begin{array}{l}{b}_1=7\\ b_2=13\\ h=5\end{array}$

Thus

  $\begin{array}{l}A=\frac{1}{2}h(b_1+b_2)\\ A=\frac{5}{2}(7+13)\\ A=\frac{100}{2}\\ A=50sq.unit\end{array}$

Now

Median of the trapezoid.

  $\begin{array}{l}M=\frac{1}{2}(b_1+b_2)\\ M=\frac{1}{2}(7+13)\\ M=\frac{20}{2}\\ M=10\end{array}$

Hence, area of the trapezoid is $A=50sq.unit$ and median is $M=10$.