Chapter 11.1, Problem 4CE

To determine

To Find: The area.

Answer to Problem 4CE

  $A=49c{m}^2$

Explanation of Solution

Given: The perimeter of the square is $28cm$ .

Given:

Perimeter of square= $28cm$

Then

Perimeter of square

  $\begin{array}{l}P=4s\\ 28=4(s)\\ \frac{28}{4}=s\\ s=7cm\end{array}$

The side of the square is $7cm$

Now,

Area of square

  $\begin{array}{l}A=s^2\\ $ A={(7)}^2$A=49c{m}^2\end{array}$

Hence, $A=49c{m}^2$