Chapter 12, Problem 33A

(a)

Interpretation Introduction

Interpretation:

The total number of valence electrons is to be calculated in the given molecule.

Concept introduction:

The valence electrons are the electrons which are present in last shell and available for bond formation.

Answer to Problem 33A

Total number of valence electrons in $CB{r}_4=32$

Explanation of Solution

Number of valence electrons in carbon=4

Number of valence electrons in each bromine=7

Therefore, Total number of valence electrons in $CB{r}_4=4+7\times 4$

  $=32$

(b)

Interpretation Introduction

Interpretation:

The total number of valence electrons is to be calculated in the given molecule.

Concept introduction:

The valence electrons are the electrons which are present in last shell and available for bond formation.

Answer to Problem 33A

Total number of valence electrons in $N{O}_2=17$

Explanation of Solution

Number of valence electrons in nitrogen=4

Number of valence electrons in each oxygen=7

Therefore, Total number of valence electrons in $N{O}_2=5+6\times 2$

  $=17$

(c)

Interpretation Introduction

Interpretation:

The total number of valence electrons is to be calculated in the given molecule.

Concept introduction:

The valence electrons are the electrons which are present in last shell and available for bond formation.

Answer to Problem 33A

Total number of valence electrons in $C_6{H}_6=30$

Explanation of Solution

Number of valence electrons in each carbon=4

Number of valence electrons in each hydrogen=1

Therefore, Total number of valence electrons in $C_6{H}_6=4\times 6+1\times 6$

  $=30$

(a)

Interpretation Introduction

Interpretation:

The total number of valence electrons is to be calculated in the given molecule.

Concept introduction:

The valence electrons are the electrons which are present in last shell and available for bond formation.

Answer to Problem 33A

Total number of valence electrons in $H_2{O}_2=14$

Explanation of Solution

Number of valence electrons in each hydrogen=1

Number of valence electrons in each oxygen=6

Therefore, Total number of valence electrons in $H_2{O}_2=2\times 1+6\times 2$

  $=14$