Chapter 12, Problem 45A

Interpretation Introduction

Interpretation:

The partial pressure of water vapor in air sample needs to be determined.

Concept introduction:

Partial pressure of gas is the product of mole fraction of that gas and total pressure of mixture.

Answer to Problem 45A

The partial pressure of water vapor is $0.01$ atm.

Explanation of Solution

According to the Dalton’s law of partial pressure, the total pressure of mixture is equal to sum of partial pressure of individual gas in the mixture.

Thus, $P_{total}=P_A+P_B+P_C+\mathrm{......}$

Where $P_{total}=$ total pressure of mixture

$P_{A,}{P}_B\&P_C$ are partial pressure of gases.

Thus, $P_T=P_A+P_B+P_C+P_D$

$1.000=0.79+0.20+0.0044+P_W$

$P_W=1.00-0.79-0.20-0.0044=0.01atm$

$0.01$ atm is the partial pressure of water vapors.