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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

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BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 12, Problem 77AE
Textbook Problem
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At a certain temperature, K = 1.1 × l03 for the reaction

Fe 3 + ( a q ) + SCN ( a q ) FeSCN 2 + ( a q )

Calculate the concentrations of Fe3+, SCN , and FeSCN2+ at equilibrium if 0.020 mole of Fe(NO3)3 is added to 1.0 L of 0.10 M KSCN. (Neglect any volume change.)

Interpretation Introduction

Interpretation: The equilibrium constant for the production of FeSCN2+(aq) is given. The equilibrium concentration of all species of this reaction is to be calculated when given mole of Fe(NO3)3 is added to 1.0L of 0.10M KSCN .

Concept introduction: The state when the reactants involved in a chemical reaction and the products formed in the reaction exist in concentrations having no further tendency to change is known as an equilibrium state of the reaction.

For a reaction,

jA+kBlC+mD

The equilibrium constant is given by,

K=[C]l[D]m[A]j[B]k

To determine: The equilibrium concentration of [FeSCN2+] , [SCN] and [Fe3+] for the given reaction.

The equilibrium concentration of [FeSCN2+] is 0.0198M_ .

Explanation of Solution

Explanation

Given

The equilibrium constant is 1.1×103 .

The 0.020mole of Fe(NO3)3 is added to 1.0L of 0.10M KSCN .

The given reaction is,

Fe3+(aq)+SCN(aq)FeSCN2+(aq)

In this reaction, one mole of Fe(NO3)3 reacts with one mole of KSCN .

Since, the value of K is very large (K>>1) . Therefore, product will dominate.

It is assumed that 0.020M of Fe3+ react completely and the change in concentration of Fe3+(aq) is x .

Make the ICE table for the given reaction.

Fe3+(aq)SCN(aq)FeSCN2+(aq)Initial(M):00.100.020Change(M):x0.020+xxEquilibrium(M):x0.08+x0.020x

The equilibrium constant for the given reaction is,

K=[FeSCN2+][Fe3+][SCN]

Where,

  • K is the equilibrium constant.

Substitute the value of K and equilibrium concentration values in the above expression.

K=[FeSCN2+][Fe3+][SCN]1

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Chapter 12 Solutions

Chemistry: An Atoms First Approach
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