Chapter 13.10, Problem 11PPS

To determine

The probability ofoutcome of candies.

P (two green candies)

Answer to Problem 11PPS

The probability of outcome of candiesis P (two green candies)= $\frac{1}{12}$

Explanation of Solution

Given:

Blue: $6$

Red:$3$

Green: $5$

Yellow: $2$

Total Candies: $6+3+5+2=16$

Calculation:

Fraction Form:

As calculate first green candy and then second green candy, in first green candy get the total number of green candy and total number of candies.

In second green candy remove $1$ green candy from the total green candies and total number of candies, so

P (First candy is green) = $\frac{5}{16}$

P (Second candy is green) = $\frac{4}{15}$

P (two green candies) = P (first) * P (second)

  $\begin{array}{l}=\frac{5}{16}\times \frac{4}{15}\\ =\left(\frac{5.4}{16.15}\right)\\ =\frac{20}{240}\\ =\frac{1}{12}\end{array}$

Conclusion:

Hence, P (two green candies)= $\frac{1}{12}$