Chapter 13.6, Problem 5CYU

To determine

The probability of the 2 coins heads.

Answer to Problem 5CYU

There is $25\%$ chance of getting both heads from tossing $2$ coins.

Explanation of Solution

In the Fraction Form:

To find the $P\left(\text{both}\text{heads}\right)$ have to make a sample space when tossing both coins that is,

	H	T
H	$\left(H,H\right)$	$\left(H,T\right)$
T	$\left(T,H\right)$	$\left(T,T\right)$

By looking at the table out of $4$ outcomes choose that must be heads $\left(H\right)$ from the both coins. That is, $\left(H,H\right)$

That is $1$ outcomes. So $P\left(bothheads\right)$ or $P\left(H,H\right)$ is given as

  $P\left(bothheads\right)=\frac{1}{4}$

In the Percent Form:

to convert from a fraction to the percent form, multiply the given fraction by $100$ and finally place $\%$ at the end of the number. That is,

  $\begin{array}{l}=\frac{1}{4}\times 100\%\\ =\left(\frac{100}{4}\right)\%\\ =25\%\end{array}$

So there is $25\%$ chance of getting both heads from tossing $2$ coins.

Conclusion:

Hence, there is $25\%$ chance of getting both heads from tossing $2$ coins.