Chapter 13.10, Problem 13PPS

To determine

The probability ofoutcome of candies.

P (a yellow then a blue candy)

Answer to Problem 13PPS

The probability of outcome of candiesis P (a yellow then a blue candy)= $\frac{1}{20}$

Explanation of Solution

Given:

Blue: $6$

Red: $3$

Green: $5$

Yellow: $2$

Total Candies: $6+3+5+2=16$

Calculation:

Fraction Form:

So calculate the probability of yellow candy first and then calculate the blue candies probability.

P (First candy is yellow) = $\frac{2}{16}=\frac{1}{8}$

P (Second candy is blue) = $\frac{6}{15}=\frac{2}{5}$

This is the probability after removing the $1$ yellow candy is removed.

P (Yellow and then Blue candy) = P (Yellow) * P (blue)

  $\begin{array}{l}=\frac{1}{8}\times \frac{2}{5}\\ =\left(\frac{1.2}{8.5}\right)\\ =\frac{2}{40}\\ =\frac{1}{20}\end{array}$

Conclusion:

Hence, P (a yellow then a blue candy)= $\frac{1}{20}$