Chapter 13.6, Problem 3CYU

To determine

  $\text{P}\left(\text{greater than 6}\right)$ is to be estimated.

Answer to Problem 3CYU

In fraction form,

  $\text{P}\left(\text{greater than 6}\right)\text{=}\frac{\text{2}}{\text{5}}$

Explanation of Solution

Given:

The spinner is spun once which is shown below

  

Calculation:

There are $\text{10}$ total sections on spinner.

So the number of total outcomes becomes $\text{10}$ .

To find that how many of these $\text{10}$ sections contain numbers greater than $\text{6}$ ,

The numbers greater than $6$ occurred on the spinner are $\text{7,8,9,10}$

  $\text{4}$ Out of $\text{10}$ parts contain the numbers greater than $\text{6}$ .

The probability that the numbers greater than $\text{6}$ are occurred can be calculated by formula,

  $P=\frac{\text{Number of desired outcomes}}{\text{Number of total outcomes}}$

Substituting the values in above formula,

  $\text{P}\left(\text{greater than 6}\right)\text{=}\frac{\text{4}}{\text{10}}$

  $\text{P}\left(\text{greater than 6}\right)\text{=}\frac{\text{2}}{\text{5}}$

Conclusion:

Hence, $\text{P}\left(\text{greater than 6}\right)\text{=}\frac{\text{2}}{\text{5}}$