Chapter 13.6, Problem 4CYU

To determine

  $\text{P}\left(\text{Less than 5}\right)$ is to be estimated.

Answer to Problem 4CYU

In fraction form,

  $\text{P}\left(\text{Less than 5}\right)\text{=}\frac{\text{2}}{\text{5}}$

Explanation of Solution

Given:

The spinner is spun once which is shown below

  

Calculation:

There are $\text{10}$ total sections on spinner.

So the number of total outcomes becomes $\text{10}$ .

To find that how many of these $\text{10}$ sections contain numbers less than $\text{5}$ ,

The numbers less than $\text{5}$ occurred on the spinner are $\text{1,2,3,4}$ .

  $\text{4}$ Out of $\text{10}$ parts contain the numbers less than $\text{5}$ .

The probability that the numbers less than $\text{5}$ are occurred can be calculated by formula,

  $\text{=}\frac{\text{Number of desired outcomes}}{\text{Number of total outcomes}}$

Substituting the values in above formula,

  $\begin{array}{l}\text{P}\left(\text{Less than 5}\right)\text{=}\frac{\text{4}}{\text{10}}\\ \text{P}\left(\text{Less than 5}\right)\text{=}\frac{\text{2}}{\text{5}}\end{array}$

Conclusion:

Hence, $\text{P}\left(\text{Less than 5}\right)\text{=}\frac{\text{2}}{\text{5}}$