Chapter 13.9, Problem 8PPS

To determine

To calculate: No. of ways that can the contestants finish first, second, third and fourth.

Answer to Problem 8PPS

There are $32760$ no. of ways that the contestant finish first, second and third and fourth.

Explanation of Solution

Given information:

No of contestants $=15$ .

Calculation: There are total $15$ contestants in a spelling bee.

A permutation is an arrangement or listing in which the order is important.

Whereas selecting the position, order is important.

So permutation is used.

So there are total $15$ choices for the first position,

  $14$ choices for the third position,

  $12$ choices for the fourth position.

The no. of ways the contestant finish first, second, third and fourth position is as below:

  $\begin{array}{l}P\left(15,4\right)=15\times 14\times 13\times 12\\ =32760\end{array}$