Prescott's Microbiology
11th Edition
ISBN: 9781260409062
Author: WILLEY, Joanne
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Textbook Question
Chapter 13.4, Problem 3CC
Briefly discuss the general organization of tRNA and rRNA genes. How does their expression differ from that of protein-coding genes with respect to posttranscriptional modification of the gene product?
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There are similarities and differences during regulation of gene expression in both prokaryotes and eukaryotes. Promoters, transcription factors and RNA polymerase are essential elements in transcription but their properties and function may differ.a) Predict the outcome or consequences of mRNA transcription by RNA polymerase II in eukaryote without the presence of transcription factors (TF).
a) What is a mutation in molecular terms? b) a mutation deletes a base in the genomic DNA discuss how that will affect the reading frame and expression product production.
Using the following list of codons describe, using diagrams etc., how information stored in
the DNA is translated into a peptide. Be sure to discuss all steps. In other words, use a diagram and give me sequences, transcription and translation steps. Show the sequences of the sense and the other DNA strand, the mRNA and the tRNA’s.
UUU -phenylalanine UCU -serine AUG –initiation/methionine
CUU -leucine ACU -threonine
GUU -valine UAA -Termination
Regarding eukaryotic genes, it is correct to state that: *
A) Distal enhancer-like elements decrease the intensity of gene transcription activation B)Mutations in intronic regions of a gene can alter the levels of its corresponding protein
C)They are regulated only by promoter regions, being activated or repressed by the presence of transcription factors
D)The junctions of exons and introns are recognized by splicing factors, which ensure the production of the same mRNA regardless of cell type.
E) Activator and repressor proteins bind to the coding region of genes, regulating the intensity of their transcription
Chapter 13 Solutions
Prescott's Microbiology
Ch. 13.1 - MICRO INQUIRY Based on what we now know about...Ch. 13.1 - Prob. 2MICh. 13.1 - Retrieve, Infer, Apply 1. Briefly summarize the...Ch. 13.1 - Retrieve, Infer, Apply 2. Explain how protein was...Ch. 13.2 - MICRO INQUIRY To which carbon of ribose...Ch. 13.2 - MICRO INQUIRY How many H bonds are there between...Ch. 13.2 - Prob. 3MICh. 13.2 - Prob. 1CCCh. 13.2 - Retrieve, Infer, Apply What does it mean to say...Ch. 13.2 - Retrieve, Infer, Apply Amino acids are described...
Ch. 13.3 - MICRO INQUIRY What provides the energy to fuel...Ch. 13.3 - MICRO INQUIRY What is the difference between...Ch. 13.3 - MICRO INQUIRY Why cant DNA polymerase I perform...Ch. 13.3 - Retrieve, Infer, Apply How many replicons do...Ch. 13.3 - Prob. 2CCCh. 13.3 - Retrieve, Infer, Apply Describe the nature and...Ch. 13.3 - Retrieve, Infer, Apply Outline the steps Involved...Ch. 13.3 - Retrieve, Infer, Apply What is the end replication...Ch. 13.4 - Why is the nontemplate strand called the sense...Ch. 13.4 - Retrieve, Infer, Apply The coding region of a gene...Ch. 13.4 - Which strand of a gene has sequences that...Ch. 13.4 - Briefly discuss the general organization of tRNA...Ch. 13.5 - MICRO INQUIRY Are the -35 and -10 regions...Ch. 13.5 - Retrieve, Infer, Apply Outline the transcription...Ch. 13.5 - Retrieve, Infer, Apply What is a polycistronic...Ch. 13.5 - Retrieve, Infer, Apply What is a consensus...Ch. 13.5 - Tabulate the similarities and differences between...Ch. 13.6 - Prob. 1MICh. 13.6 - What is the difference between a codon and an...Ch. 13.6 - Prob. 2CCCh. 13.6 - Retrieve, Infer, Apply What is meant by code...Ch. 13.6 - Retrieve, Infer, Apply Is the genetic code truly...Ch. 13.7 - MICRO INQUIRY Why is simultaneous transcription...Ch. 13.7 - MICRO INQUIRY What would be the outcome if an...Ch. 13.7 - MICRO INQUIRY Why would it be impossible for...Ch. 13.7 - MICRO INQUIRY What provides the energy to fuel...Ch. 13.7 - Retrieve, Infer, Apply In which direction are...Ch. 13.7 - Retrieve, Infer, Apply Briefly describe the...Ch. 13.7 - Retrieve, Infer, Apply What are the translational...Ch. 13.7 - Prob. 4CCCh. 13.7 - Retrieve, Infer, Apply How many ATP and GTP...Ch. 13.8 - Prob. 1CCCh. 13.8 - Prob. 2CCCh. 13.8 - Retrieve, Infer, Apply Give the major...Ch. 13.8 - Prob. 4CCCh. 13 - Prob. 1RCCh. 13 - Prob. 2RCCh. 13 - Prob. 3RCCh. 13 - Prob. 4RCCh. 13 - Prob. 5RCCh. 13 - Streptomyces coelicolor has a linear chromosome....Ch. 13 - You have isolated several E. coli mutants: Mutant...Ch. 13 - Prob. 3ALCh. 13 - Prob. 4AL
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Define both transcription and translation. In addition, describe the role(s) of each of the following in the processes of gene expression and protein synthesis: DNA, mRNA, tRNA, rRNA, ribosome(s), RNA polymerase, codon, anticodon, amino acid(s) and polypeptide(s). Be detailed in your answer.arrow_forwardIn a eukaryotic cell, four general types of RNA molecules are involved in gene expression. a) What are these four types of RNA? 2. b) Which is not involved in gene expression in prokaryotic cells? Why not?arrow_forwardThe pre-mRNA transcript and protein made by several mutant genes were examined. The results are given below. Determine where in the gene a likely mutation lies: the promoter region, exon, intron, cap on mRNA, or ribosome binding site. a. normal-length transcript, normal-length nonfunctional protein b. normal-length transcript, no protein made c. normal-length transcript, normal-length mRNA, short nonfunctional protein d. normal-length transcript, longer mRNA, shorter nonfunctional protein e. transcript never madearrow_forward
- Gene X codes for a protein in eukaryotes. A mutated eukaryotic cell contains an altered base-pair in an intron of gene X. Which would be the most likely effect of this mutation on the biomolecules in the cell? The amount of pre-mRNA transcribed from gene X would be less than normal. The amount of functional protein corresponding to gene X would be less than normal. The ability of snRNAs to form a spliceosome would be diminished. The breakdown of mature mRNA corresponding to gene X would be fasterarrow_forwardSelect the three post-transcriptional modifications often seen in the processing of mRNA in eukaryotes: Group of answer choices heteroduplex formation; base modification; capping 3'-capping; 5'-poly(A) tail addition; splicing 5'-poly(A) tail addition; insertion of introns; capping removal of exons; insertion of introns; capping 5'-capping; 3'-poly(A) tail addition; splicingarrow_forwardExplain how the expression of a single gene can be quickly,efficiently,and specifically shut down at the transcriptional,posttranscriptional,and posttranslational stages through thecoordinated expression of a transcriptional repressor, an miRNA,and a ubiquitin ligase.arrow_forward
- Consider this list (below) of steps involved in transcription. These steps are out of order. TRANSCRIPTION: 1. mRNA travels through a nuclear pore and enters the cytoplasm 2. the mRNA polymerase attaches at the start of a specific gene 3. RNA polymerase reads the gene surface4. a transcription factor bonds to a promoter site5. DNA molecule is unwound 6. a complimentary mRNA is produced What is the correct order of this transcription?arrow_forwardThe following four mutations have been discovered in a gene that has more than 60 exons and encodes a very large protein of 2532 amino acids. Indicate which mutation would likely cause a detectable change in the size of the mRNA and/or the size of the protein product. Consider a detectable change to be >10% of the wild-type size. A table of the genetic code is shown below. First letter 0 00 U O A บบบ UUC UUA UUG U CUU CUC CUA CUG Phe GUU GUC GUA GUG Leu >Leu AUU AUC lle AUA AUG Met >Val UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Second letter C Ser Pro Thr Ala CAU CAC CAA CAG UAU UGU Tyr UAC UGC UAA Stop UGA UAG Stop UGG AAU AAC AAA AAG A GAU GAC GAA GAG His Gin Asn Lys Asp G Glu CGU CGC CGA CGGJ AGU AGC AGA AGG GGU GGC GGA GGG O AAG576UAG (changes codon 576 from AAG to UAG) Cys Stop Trp O GUG326AUG (changes codon 326 from GUG to AUG) Arg Ser Arg Gly DUAG DUA G DCAG DO AG deletion of codon 779 insertion of 1000 base pairs into the sixth intron (this particular…arrow_forwardFor each of the following, identify whether that sequence or feature of a typical protein-coding gene would be recognizable in the specified molecule in a typical prokaryotic cell. 5' UTR in DNA? 5' UTR in mRNA? Shine-Dalgarno in DNA? Shine-Dalgarno in polypeptide? Promoter in RNA? Promoter in polypeptide sequence? Stop codon in mRNA? Stop codon in the polypeptide sequence? [Choose ] [Choose ] [Choose ] [Choose ] [Choose ] [Choose ] [Choose ] [Choose ] > <arrow_forward
- Draw the SMN2 pre-mRNA (10 exons and 9 introns), indicate the 5’ and 3’ SS location. Draw the SMN2 mature mRNA before treatment with Spinraza. What type of alternative splicing is occurring? Draw the SMN2 mature mRNA after treatment with Spinrazaarrow_forwardOne procedure of obtaining cDNA from mRNA is by using oligo(dT) primers. What are oligo(dT)s? Why does using them make sense based on the processing (or modification) of precursor mRNA to get mature mRNA?arrow_forwardRegarding the process of gene transcription in eukaryotes, it is correct to state that A)The transcription process is terminated when the RNA polymerase complex reaches the final region of the gene with the poly-adenylation signal. B)The RNA polymerase II transcription elongation complex contains transcription factors such as the TATA box binding protein C)The opening of the region of DNA that will be transcribed is done by the DNA helicase, present in the transcription complex. D)The main function of the Mediator coactivator is to promote the transition between elongation and completion of the transcription process. E)Different activators and repressors can influence the transcriptional elongation complex by binding to the promoter regions of genesarrow_forward
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