Chapter 13.4, Problem 3WE

To determine

To make a sketch, then find $\overrightarrow{AB}$ and $\left|\overrightarrow{AB}\right|$ of a points $A\left(6,1\right)$ and $B\left(4,3\right)$ .

Answer to Problem 3WE

The required solution are,

Sketch is,

  

  $\overrightarrow{AB}=\left(-2,2\right)$ and $\left|\overrightarrow{AB}\right|=2\sqrt{2}$ .

Explanation of Solution

Given information: The points are $A\left(6,1\right)$ and $B\left(4,3\right)$ .

Calculation: The required solution are obtained as,

The sketch of points $A\left(6,1\right)$ and $B\left(4,3\right)$ is,

  

  $\overrightarrow{AB}$ obtained as,

  $\overrightarrow{AB}=\left(x_2-x_1,y_2-y_1\right)=\left(4-6,3-1\right)=\left(-2,2\right)$

  $\left|\overrightarrow{AB}\right|$ obtained as,

  $\left|\overrightarrow{AB}\right|=\sqrt{x^2+y^2}=\sqrt{{\left(-2\right)}^2+2^2}=\sqrt{8}=2\sqrt{2}$

Hence, the required solution are, $\overrightarrow{AB}=\left(-2,2\right)$ and $\left|\overrightarrow{AB}\right|=2\sqrt{2}$ .