Chapter 13.9, Problem 1ST2

To determine

To find the value of slope and $y$ -intercept of the given line.

Answer to Problem 1ST2

The value of slope and $y$ -intercept of the line $2x-5y=20$ are $m$$=$$\frac{2}{5}$ and $c$$=$$-4$ respectively.

Explanation of Solution

Given information:

The equation of the line is given: $2x-5y=20$ .

The slope-intercept form of a linear equation: $y=mx+c$

Where, $m$ is denoted as slope and $c$ is denoted as $y$ -intercept.

Here,

  $\begin{array}{l}2x-5y=20\\ -5y=20-2x\\ y=\frac{20-2x}{-5}=\frac{20}{-5}-\left(\frac{2x}{-5}\right)=-4+\frac{2x}{5}\\ y=\frac{2x}{5}-4\\ y=\left(\frac{2}{5}\right)x+\left(-4\right)\end{array}$

From the above equation, it can be observed that the value of slope and $y$ -intercept of the given equation are $m$$=$$\frac{2}{5}$ and $c$$=$$-4$ respectively.