McDougal Littell Jurgensen Geometry: Student Edition Geometry
McDougal Littell Jurgensen Geometry: Student Edition Geometry
5th Edition
ISBN: 9780395977279
Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Publisher: Houghton Mifflin Company College Division
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Chapter 13, Problem 21CR
To determine

To graph: The point of intersection of the two given lines.

Expert Solution & Answer
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Answer to Problem 21CR

The point of intersection of the two given lines is (2,1) .

Explanation of Solution

Given information: The given equations of line are y=2x3 and x+2y=4 .

Graph:

To find the coordinates of the lines, consider the expression of given equation:

  y=2x3

Substitute 0 for x in the above expression.

  y=2(0)3=3

Therefore, first coordinate of the line is (0,3) .

To determine second coordinate, substitute 1.5 for x in the above expression.

  y=2(1.5)3=0

Therefore, second coordinate of the line is (1.5,0) .

To determine third coordinate, substitute 2 for x in the above expression.

  y=2(2)3=1

Therefore, third coordinate of the line is (2,1) .

To find the coordinates of the lines, consider the expression of given equation:

  x+2y=42y=x+4y=x2+2

Substitute 0 for x in the above expression.

  y=02+2=2

Therefore, first coordinate of the line is (0,2) .

To determine second coordinate, substitute 2 for x in the above expression.

  y=22+2=1+2=1

Therefore, second coordinate of the line is (2,1) .

To determine third coordinate, substitute 4 for x in the above expression.

  y=42+2=2+2=0

Therefore, third coordinate of the line is (4,0) .

Plot and connect the ordered pair of the equation of line x+2y=4 are (0,2) , (2,1) and (4,0) and coordinates of the equation of line y=2x3 through which it is passing are (0,3) , (1.5,0) and (2,1) on the coordinate graph as shown below:

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 13, Problem 21CR

Therefore, the point of intersection of the two given lines from the above graph is (2,1) .

Chapter 13 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 13.1 - Prob. 11CECh. 13.1 - Prob. 12CECh. 13.1 - Prob. 1WECh. 13.1 - Prob. 2WECh. 13.1 - Prob. 3WECh. 13.1 - Prob. 4WECh. 13.1 - Prob. 5WECh. 13.1 - Prob. 6WECh. 13.1 - Prob. 7WECh. 13.1 - Prob. 8WECh. 13.1 - Prob. 9WECh. 13.1 - Prob. 10WECh. 13.1 - Prob. 11WECh. 13.1 - Prob. 12WECh. 13.1 - Prob. 13WECh. 13.1 - Prob. 14WECh. 13.1 - Prob. 15WECh. 13.1 - Prob. 16WECh. 13.1 - Prob. 17WECh. 13.1 - Prob. 18WECh. 13.1 - Prob. 19WECh. 13.1 - Prob. 20WECh. 13.1 - Prob. 21WECh. 13.1 - Prob. 22WECh. 13.1 - Prob. 23WECh. 13.1 - Prob. 24WECh. 13.1 - Prob. 25WECh. 13.1 - Prob. 26WECh. 13.1 - Prob. 27WECh. 13.1 - Prob. 28WECh. 13.1 - Prob. 29WECh. 13.1 - Prob. 30WECh. 13.1 - Prob. 31WECh. 13.1 - Prob. 32WECh. 13.1 - Prob. 33WECh. 13.1 - Prob. 34WECh. 13.1 - Prob. 35WECh. 13.1 - Prob. 36WECh. 13.1 - Prob. 37WECh. 13.1 - Prob. 38WECh. 13.1 - Prob. 39WECh. 13.1 - Prob. 40WECh. 13.1 - Prob. 41WECh. 13.1 - Prob. 42WECh. 13.1 - Prob. 43WECh. 13.1 - Prob. 44WECh. 13.1 - Prob. 45WECh. 13.1 - Prob. 3ECh. 13.2 - 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