Chapter 13.3, Problem 3WE

To determine

To find the slope of $\overline{OE},\overline{GF},\overline{OG},\overline{EF}$ .

Answer to Problem 3WE

Slope of $\overline{OE}$ is equals to slope of $\overline{GF}$ which is $\frac{7}{2}$

and slope of $\overline{OG}$ is equals to slope of $\overline{EF}$ which is $0$ .

Explanation of Solution

Given:

Below is the figure

  

Calculation:

Slope of a line when two points $\left(x_1,y_1\right)$ and $\left(x_2,y_2\right)$ are given is

  $m=\frac{y_2-y_1}{x_2-x_1}$

Points are $O\left(0,0\right),E\left(2,7\right)$ .

  $m_{OE}=\frac{7-0}{2-0}=\frac{7}{2}$

Side $\overline{OG}$ coincides with $x-axis$

So, $m_{OG}=0$

Since, $OEFG$ is a parallelogram so slope of $\overline{OE}$ is equals to slope of $\overline{GF}$ which is $\frac{7}{2}$

And slope of $\overline{OG}$ is equals to slope of $\overline{EF}$ which is $0$ .