Chapter 13.8, Problem 4WE

To determine

To find: The missing vertex of isosceles triangle

Answer to Problem 4WE

The missing vertex is $\left(\frac{g+h}{2},0\right)$ .

Explanation of Solution

Given information:Two vertices of the isosceles triangle are $(g,0)$ and $(h,0)$ .

  

Calculation:

Let us give the name to the triangle as $\Delta ABC$ , where $A\equiv (g,0)$ , $B\equiv (?,j)$ and $C\equiv (h,0)$

Since $\Delta ABC$ is isosceles triangle

  $\therefore AB=BC$

The vertex $B$ can be labeled as $\left(\frac{g+h}{2},0\right)$ .

Hence,

The missing vertex is $\left(\frac{g+h}{2},0\right)$ .