Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
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Chapter 15, Problem 15.111QE

(a)

Interpretation Introduction

Interpretation:

The solution of  0.250 M HBr has to be classified as either strongly acidic, weakly acidic, neutral, weakly basic, and strongly basic and also determine pH of solution.

Concept Introduction:

The formula to calculate pH is given as follows:

  pH=log[H3O+]

(b)

Interpretation Introduction

Interpretation:

The solution of  0.50 M HF has to be classified as either strongly acidic, weakly acidic, neutral, weakly basic, and strongly basic and also determine pH of solution.

Concept Introduction:

The ionization of a hypothetical weak acid (HA) is given as follows:

  HA(aq)+H2O(l)A(aq)+H3O+(aq)

(c)

Interpretation Introduction

Interpretation:

Solution of  0.020 M Ba(OH)2 has to be classified as either strongly acidic, weakly acidic, neutral, weakly basic, and strongly basic and also determine pH of solution.

Concept Introduction:

Refer to part (a).

(d)

Interpretation Introduction

Interpretation:

Solution of  0.44 M NH3 has to be classified as either strongly acidic, weakly acidic, neutral, weakly basic, and strongly basic and also determine pH of solution.

Concept Introduction:

The ionization of a hypothetical weak base is given as follows:

  B(aq)+H2O(l)BH+(aq)+OH(aq)

The expression of Kb is given as follows:

  Kb=[BH+][OH][B]

Here,

[B] denotes the concentration of hypothetical weak base.

[OH] denotes the concentration of OH ions.

[BH+] denotes the concentration of BH+ ions.

Kb denotes ionization constant of weak base.

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Chapter 15 Solutions

Chemistry: Principles and Practice

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