Use half-reactions to balance the following equations in the acidic solution: Mn ( s ) + Cr 3+ ( aq ) → Mn 2+ ( aq ) + Cr ( s ) Concept introduction: Here are the steps to balance redox reaction sin an acidic medium: Determine the oxidation numbers of the elements to figure out the oxidation and reduction half of the equation. To balance every half reaction in acidic medium, use H 2 O to balance O, use H+ to balance H, and finally use electrons to balance the net charge.

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Answer 1

Question

Chapter 15, Problem 15.78CQ

Interpretation Introduction

Interpretation:

Use half-reactions to balance the following equations in the acidic solution:

Mn(s) + Cr3+(aq)→Mn2+(aq) + Cr(s)

Concept introduction:Here are the steps to balance redox reaction sin an acidic medium:
Determine the oxidation numbers of the elements to figure out the oxidation and reduction half of the equation.

To balance every half reaction in acidic medium, use H₂O to balance O, use H+ to balance H, and finally use electrons to balance the net charge.

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Answer 2

Question

Chapter 15, Problem 15.78CQ

Interpretation Introduction

Interpretation:

Use half-reactions to balance the following equations in the acidic solution:

Mn(s) + Cr3+(aq)→Mn2+(aq) + Cr(s)

Concept introduction:Here are the steps to balance redox reaction sin an acidic medium:
Determine the oxidation numbers of the elements to figure out the oxidation and reduction half of the equation.

To balance every half reaction in acidic medium, use H₂O to balance O, use H+ to balance H, and finally use electrons to balance the net charge.

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Answer 3

Question

Chapter 15, Problem 15.78CQ

Interpretation Introduction

Interpretation:

Use half-reactions to balance the following equations in the acidic solution:

Mn(s) + Cr3+(aq)→Mn2+(aq) + Cr(s)

Concept introduction:Here are the steps to balance redox reaction sin an acidic medium:
Determine the oxidation numbers of the elements to figure out the oxidation and reduction half of the equation.

To balance every half reaction in acidic medium, use H₂O to balance O, use H+ to balance H, and finally use electrons to balance the net charge.

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Answer 4

Question

Chapter 15, Problem 15.78CQ

Interpretation Introduction

Interpretation:

Use half-reactions to balance the following equations in the acidic solution:

Mn(s) + Cr3+(aq)→Mn2+(aq) + Cr(s)

Concept introduction:Here are the steps to balance redox reaction sin an acidic medium:
Determine the oxidation numbers of the elements to figure out the oxidation and reduction half of the equation.

To balance every half reaction in acidic medium, use H₂O to balance O, use H+ to balance H, and finally use electrons to balance the net charge.

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Answer 5

Chapter 15, Problem 15.78CQ

Interpretation Introduction

Interpretation:

Use half-reactions to balance the following equations in the acidic solution:

Mn(s) + Cr3+(aq)→Mn2+(aq) + Cr(s)

Concept introduction:Here are the steps to balance redox reaction sin an acidic medium:
Determine the oxidation numbers of the elements to figure out the oxidation and reduction half of the equation.

To balance every half reaction in acidic medium, use H₂O to balance O, use H+ to balance H, and finally use electrons to balance the net charge.

Answer 6

Chapter 15, Problem 15.78CQ

Interpretation Introduction

Interpretation:

Use half-reactions to balance the following equations in the acidic solution:

Mn(s) + Cr3+(aq)→Mn2+(aq) + Cr(s)

Concept introduction:Here are the steps to balance redox reaction sin an acidic medium:
Determine the oxidation numbers of the elements to figure out the oxidation and reduction half of the equation.

To balance every half reaction in acidic medium, use H₂O to balance O, use H+ to balance H, and finally use electrons to balance the net charge.

Answer 7

Chapter 15, Problem 15.78CQ

Interpretation Introduction

Interpretation:

Use half-reactions to balance the following equations in the acidic solution:

Mn(s) + Cr3+(aq)→Mn2+(aq) + Cr(s)

Concept introduction:Here are the steps to balance redox reaction sin an acidic medium:
Determine the oxidation numbers of the elements to figure out the oxidation and reduction half of the equation.

To balance every half reaction in acidic medium, use H₂O to balance O, use H+ to balance H, and finally use electrons to balance the net charge.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 15.1 - Prob. 15.1QAP Ch. 15.1 - Prob. 15.2QAP Ch. 15.1 - Prob. 15.3QAP Ch. 15.1 - Prob. 15.4QAP Ch. 15.1 - Prob. 15.5QAP Ch. 15.1 - Prob. 15.6QAP Ch. 15.1 - Prob. 15.7QAP Ch. 15.1 - Prob. 15.8QAP Ch. 15.1 - Prob. 15.9QAP Ch. 15.1 - Prob. 15.10QAP

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