Basic Chemistry (5th Edition)
Basic Chemistry (5th Edition)
5th Edition
ISBN: 9780134138046
Author: Karen C. Timberlake
Publisher: PEARSON
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Chapter 15.2, Problem 15.26QAP
Interpretation Introduction

(a)

Interpretation:

To balance the following equation in basic medium:

  Al(s)+ClO-(aq.)AlO2-(aq)+Cl-(aq.)

Concept Introduction:

In basic medium, the overall reaction contains only hydroxide ion other that given reactants and products.

Steps to be followed to balance a reaction in Basic medium:

  • Break the reaction into different half-cell reactions.
  • Balanced all the atoms other that H and O in both half-cell reaction separately.
  • Balance the O-atom by adding water molecule to either side in the both half-cell reaction separately.
  • Balance the H-atom by adding H+ ion separately in both the half- cell reaction.
  • Balance the charge by adding electrons to either side in both half-cell reaction separately.
  • Multiply both half-cell with an integer such that on adding up both reactions, electrons got cancel out and adjust H2O molecules such that only one side contain H2O molecule.
  • Now add equal moles of OH- ions to both sides as we have H+ ions.
  • Combine H+ and OH- ions which are on same side to form water molecule and then cancel out common amount of H2O molecules from both sides.

Interpretation Introduction

(b)

Interpretation:

To balance the following equation in basic medium:

  Sn+2(aq)+IO4-(aq.)Sn+4(aq)+I-(aq.)

Concept Introduction:

In basic medium, the overall reaction contains only hydroxide ion other that given reactants and products.

Steps to be followed to balance a reaction in Basic medium:

  • Break the reaction into different half-cell reactions.
  • Balanced all the atoms other that H and O in both half-cell reaction separately.
  • Balance the O-atom by adding water molecule to either side in the both half-cell reaction separately.
  • Balance the H-atom by adding H+ ion separately in both the half- cell reaction.
  • Balance the charge by adding electrons to either side in both half-cell reaction separately.
  • Multiply both half-cell with an integer such that on adding up both reactions, electrons got cancel out and adjust H2O molecules such that only one side contain H2O molecule.
  • Now add equal moles of OH- ions to both sides as we have H+ ions.
  • Combine H+ and OH- ions which are on same side to form water molecule and then cancel out common amount of H2O molecules from both sides.

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Chapter 15 Solutions

Basic Chemistry (5th Edition)

Ch. 15.1 - Prob. 15.11QAPCh. 15.1 - Prob. 15.12QAPCh. 15.1 - Prob. 15.13QAPCh. 15.1 - Prob. 15.14QAPCh. 15.1 - Prob. 15.15QAPCh. 15.1 - Prob. 15.16QAPCh. 15.1 - Prob. 15.17QAPCh. 15.1 - Prob. 15.18QAPCh. 15.1 - Prob. 15.19QAPCh. 15.1 - Prob. 15.20QAPCh. 15.2 - Prob. 15.21QAPCh. 15.2 - Prob. 15.22QAPCh. 15.2 - Use the half-reaction method to balance each of...Ch. 15.2 - Prob. 15.24QAPCh. 15.2 - Use the halt-reaction method to balance each of...Ch. 15.2 - Prob. 15.26QAPCh. 15.3 - Prob. 15.27QAPCh. 15.3 - Prob. 15.28QAPCh. 15.3 - Prob. 15.29QAPCh. 15.3 - Prob. 15.30QAPCh. 15.3 - Prob. 15.31QAPCh. 15.3 - Prob. 15.32QAPCh. 15.3 - Prob. 15.33QAPCh. 15.3 - Prob. 15.34QAPCh. 15.3 - Prob. 15.35QAPCh. 15.3 - Prob. 15.36QAPCh. 15.4 - Prob. 15.37QAPCh. 15.4 - Prob. 15.38QAPCh. 15.4 - Prob. 15.39QAPCh. 15.4 - Prob. 15.40QAPCh. 15 - Prob. 15.41FUCh. 15 - Prob. 15.42FUCh. 15 - Prob. 15.43UTCCh. 15 - Prob. 15.44UTCCh. 15 - Prob. 15.45UTCCh. 15 - Prob. 15.46UTCCh. 15 - Prob. 15.47UTCCh. 15 - Prob. 15.48UTCCh. 15 - Prob. 15.49AUTCCh. 15 - Prob. 15.50AUTCCh. 15 - Prob. 15.51AUTCCh. 15 - Prob. 15.52AUTCCh. 15 - Prob. 15.53AUTCCh. 15 - Prob. 15.54AUTCCh. 15 - Which of the following are notation-reduction...Ch. 15 - Prob. 15.56AQAPCh. 15 - Prob. 15.57AQAPCh. 15 - Prob. 15.58AQAPCh. 15 - 15.59 Assign oxidation numbers to all the elements...Ch. 15 - Prob. 15.60AQAPCh. 15 - Assign oxidation numbers to all the elements in...Ch. 15 - Assign oxidation numbers to all the elements in...Ch. 15 - Prob. 15.63AQAPCh. 15 - Prob. 15.64AQAPCh. 15 - 15.65 Use the activity series in Table 15.3 to...Ch. 15 - Prob. 15.66AQAPCh. 15 - Prob. 15.67AQAPCh. 15 - In a voltaic cell, one half-cell consists of zinc...Ch. 15 - Prob. 15.69AQAPCh. 15 - 15.70 Use the activity series in Table 15.3 to...Ch. 15 - 15.71 In a lead storage battery. the following...Ch. 15 - Prob. 15.72AQAPCh. 15 - Prob. 15.73AQAPCh. 15 - Prob. 15.74AQAPCh. 15 - Prob. 15.75CQCh. 15 - Prob. 15.76CQCh. 15 - Prob. 15.77CQCh. 15 - Prob. 15.78CQCh. 15 - Prob. 15.79CQCh. 15 - Prob. 15.80CQCh. 15 - Prob. 15.81CQCh. 15 - The following unbalanced reaction takes place in...Ch. 15 - Prob. 15.83CQCh. 15 - Prob. 15.84CQCh. 15 - Using the activity series in Table 15.3, indicate...Ch. 15 - Using the activity series in Table 15.3, indicate...Ch. 15 - Prob. 15.87CQCh. 15 - Prob. 15.88CQ
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