   Chapter 15, Problem 28E

Chapter
Section
Textbook Problem

# Calculate the pH after 0.020 mole of NaOH is added to 1.00 L of each of the solutions in Exercise 22.

(a)

Interpretation Introduction

Interpretation:

The pH value after 0.020mole of NaOH is added to 1.00L of each of the given four solutions in Exercise 22 is to be calculated.

Concept introduction:

The pH of a solution is defined as a figure that expresses the acidity of the alkalinity of a given solution.

The pOH of a solution is calculated by the formula, pOH=log[OH]

The sum, pH+pOH=14

Explanation

Explanation

To determine the pOH

The volume of the solution is given to be 1.00L .

Therefore, the number of moles of HONH2 is 0.1mol .

The pH value of the solution formed will be affected by the OH ions from NaOH that is added to the given solution and by the OH ions from HONH2 .

Since, NaOH is a strong base, it will completely ionize to give OH ions.

Therefore, after the addition of NaOH ,

The overall [OH] =0.02+0.12=0.06M

The pOH of a solution is calculated by the formula,

pOH=log[OH]

Substitute the value of [OH] in the above expression

(b)

Interpretation Introduction

Interpretation:

The pH value after 0.020mole of NaOH is added to 1.00L of each of the given four solutions in Exercise 22 is to be calculated.

Concept introduction:

The pH of a solution is defined as a figure that expresses the acidity of the alkalinity of a given solution.

The pOH of a solution is calculated by the formula, pOH=log[OH]

The sum, pH+pOH=14

(c)

Interpretation Introduction

Interpretation:

The pH value after 0.020mole of NaOH is added to 1.00L of each of the given four solutions in Exercise 22 is to be calculated.

Concept introduction:

The pH of a solution is defined as a figure that expresses the acidity of the alkalinity of a given solution.

The pOH of a solution is calculated by the formula, pOH=log[OH]

The sum, pH+pOH=14

(d)

Interpretation Introduction

Interpretation:

The pH value after 0.020mole of NaOH is added to 1.00L of each of the given four solutions in Exercise 22 is to be calculated.

Concept introduction:

The pH of a solution is defined as a figure that expresses the acidity of the alkalinity of a given solution.

The pOH of a solution is calculated by the formula, pOH=log[OH]

The sum, pH+pOH=14

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