   Chapter 15, Problem 6P Essentials of Statistics for the B...

8th Edition
Frederick J Gravetter + 1 other
ISBN: 9781133956570

Solutions

Chapter
Section Essentials of Statistics for the B...

8th Edition
Frederick J Gravetter + 1 other
ISBN: 9781133956570
Textbook Problem

Suppose that the researcher from the previous problem repealed the study of named couples’ initials using twice as many participants and obtaining observed frequencies that exactly double the original values.The resulting data are as follows: Same Initial Different Initials   18 362 400 a. Use a chi-square test to determine whether the number of couples with the same last initial is significantly different than would be expected if couples were Hatched randomly. Test with α = .05. b. You should find that the data lead lo rejecting the null hypothesis. However, in problem 5 the decision was fail to reject. How do you explain the fact that the two samples have the same proportions but lead to different conclusions?

a.

To determine
Whether the couple with same initials is significantly different than would be expected if couples were matched randomly. (α=0.05)

Explanation

Calculation:

The hypotheses are given below:

Null hypothesis:

H0: Represents null hypothesis saying the couple with same initials is no where significantly different than would be expected if couples were randomly matched.

Alternative hypothesis:

H1: In the sample from population, there is significant difference between couples chosen.

Use α=0.05

For this problem, the degree of freedom is

df=C1=21=1

For df=1 and α=0.05, we have critical value of 3.84

b.

To determine
The Sample with same proportion but lead to different conclusions.

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