To verify that the signal at 73 ppm is consistent with an alkyne carbon or a carbon that is singly bonded to O but is inconsistent with a carbon that is part of a double bond, using table 16-4. Concept introduction: The chemical shift is moderately high for the signal at 73 ppm (Entry 3). The chemical shift is not high enough for the C atom to be a part of a double bond, but it could be part of an alkyne or it could be singly bonded to an O atom.

Question

Want to see the full answer?

Answer 1

Question

Chapter 16, Problem 16.24YT

Interpretation Introduction

Interpretation:

To verify that the signal at 73 ppm is consistent with an alkyne carbon or a carbon that is singly bonded to O but is inconsistent with a carbon that is part of a double bond, using table 16-4.

Concept introduction:

The chemical shift is moderately high for the signal at 73 ppm (Entry 3). The chemical shift is not high enough for the C atom to be a part of a double bond, but it could be part of an alkyne or it could be singly bonded to an O atom.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Between these 2 compounds, which one will be (R) and which one is (S) configuration? Please draw to explain your answer in detailed..

Determine the number of expected signals for the following compounds. (see picture attached).

answer with explanation please!!

Answer 2

Question

Chapter 16, Problem 16.24YT

Interpretation Introduction

Interpretation:

To verify that the signal at 73 ppm is consistent with an alkyne carbon or a carbon that is singly bonded to O but is inconsistent with a carbon that is part of a double bond, using table 16-4.

Concept introduction:

The chemical shift is moderately high for the signal at 73 ppm (Entry 3). The chemical shift is not high enough for the C atom to be a part of a double bond, but it could be part of an alkyne or it could be singly bonded to an O atom.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 16, Problem 16.24YT

Interpretation Introduction

Interpretation:

To verify that the signal at 73 ppm is consistent with an alkyne carbon or a carbon that is singly bonded to O but is inconsistent with a carbon that is part of a double bond, using table 16-4.

Concept introduction:

The chemical shift is moderately high for the signal at 73 ppm (Entry 3). The chemical shift is not high enough for the C atom to be a part of a double bond, but it could be part of an alkyne or it could be singly bonded to an O atom.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 16, Problem 16.24YT

Interpretation Introduction

Interpretation:

To verify that the signal at 73 ppm is consistent with an alkyne carbon or a carbon that is singly bonded to O but is inconsistent with a carbon that is part of a double bond, using table 16-4.

Concept introduction:

The chemical shift is moderately high for the signal at 73 ppm (Entry 3). The chemical shift is not high enough for the C atom to be a part of a double bond, but it could be part of an alkyne or it could be singly bonded to an O atom.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 16, Problem 16.24YT

Interpretation Introduction

Interpretation:

To verify that the signal at 73 ppm is consistent with an alkyne carbon or a carbon that is singly bonded to O but is inconsistent with a carbon that is part of a double bond, using table 16-4.

Concept introduction:

The chemical shift is moderately high for the signal at 73 ppm (Entry 3). The chemical shift is not high enough for the C atom to be a part of a double bond, but it could be part of an alkyne or it could be singly bonded to an O atom.

Answer 6

Chapter 16, Problem 16.24YT

Interpretation Introduction

Interpretation:

To verify that the signal at 73 ppm is consistent with an alkyne carbon or a carbon that is singly bonded to O but is inconsistent with a carbon that is part of a double bond, using table 16-4.

Concept introduction:

The chemical shift is moderately high for the signal at 73 ppm (Entry 3). The chemical shift is not high enough for the C atom to be a part of a double bond, but it could be part of an alkyne or it could be singly bonded to an O atom.

Answer 7

Chapter 16, Problem 16.24YT

Interpretation Introduction

Interpretation:

To verify that the signal at 73 ppm is consistent with an alkyne carbon or a carbon that is singly bonded to O but is inconsistent with a carbon that is part of a double bond, using table 16-4.

Concept introduction:

The chemical shift is moderately high for the signal at 73 ppm (Entry 3). The chemical shift is not high enough for the C atom to be a part of a double bond, but it could be part of an alkyne or it could be singly bonded to an O atom.

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 11

Ch. 16 - Prob. 16.1P Ch. 16 - Prob. 16.2P Ch. 16 - Prob. 16.3P Ch. 16 - Prob. 16.4P Ch. 16 - Prob. 16.5P Ch. 16 - Prob. 16.6P Ch. 16 - Prob. 16.7P Ch. 16 - Prob. 16.8P Ch. 16 - Prob. 16.9P Ch. 16 - Prob. 16.10P

Solution Summary: The author explains that the signal at 73 ppm is consistent with an alkyne carbon or a carbon that is singly bonded to O.

Concept explainers

Want to see the full answer?

Chapter 16 Solutions