   Chapter 16, Problem 66E

Chapter
Section
Textbook Problem

# As sodium chloride solution is added to a solution of silver nitrate, a white precipitate forms. Ammonia is added to the mixture and the precipitate dissolves. When potassium bromide solution is then added, a pale yellow precipitate appears. When a solution of sodium thiosulfate is added, the yellow precipitate dissolves. Finally, potassium iodide is added to the solution and yellow precipitate forms. Write equations for all the changes mentioned above. What conclusions can you draw concerning the sizes of the Ksp values for AgCl, AgBr, and AgI?

Interpretation Introduction

Interpretation:

It is given that, when sodium chloride is added to a solution of silver nitrate, a white precipitate is formed. This precipitate will be dissolved when ammonia is added to this mixture. Now a pale yellow precipitate will appear when a solution of potassium bromide is added to it. Now this precipitate will be dissolved when sodium thiosulfate is added and finally a yellow precipitate is formed when potassium iodide is added to this solution. The balanced equations are to be stated to explain these observations. The conclusion drawn corresponding to the size of the Ksp values for AgCl,AgBr and AgI is to be stated.

Concept introduction:

The formation of solid in a solution is known as precipitation. Solubility product, Ksp , is defined as the concentration of ions in a saturated solution where each ion is raised to the power of their coefficients.

Explanation

Explanation

To determine: The balanced equations to explain the given observations and the conclusion drawn corresponding to the sizes of the Ksp values for AgCl,AgBr and AgI

The reactions that take place are,

AgNO3(aq)+NaCl(aq)AgCl(s)+NaNO3(aq)

AgCl(aq)+2NH3(aq)Ag(NH3)2+(aq)+Cl(aq)

Ag(NH3)2+(aq)+KBr(aq)AgBr(s)+K+(aq)+2NH3(aq)

AgBr(aq)+2S2O32(aq)Ag(S2O3)23(aq)+Br(aq)

Ag(S2O3)23(aq)+KI(aq)AgI(s)+K(S2O3)23(aq)

Addition of sodium chloride to a solution of silver nitrate will lead to the formation of a precipitate of silver chloride. The color of this precipitate is white. The reaction is,

AgNO3(aq)+NaCl(aq)AgCl(s)+NaNO3(aq)

This white precipitate of silver chloride will be dissolved when ammonia is added to this mixture. The reaction is,

AgCl(aq)+2NH3(aq)Ag(NH3)2+(aq)+Cl(aq)

A pale yellow precipitate of silver bromide will be formed when potassium bromide is added to Ag(NH3)2+

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