BuyFindarrow_forward

Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097

Solutions

Chapter
Section
BuyFindarrow_forward

Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

The solubility rules outlined in Chapter 4 say that BaCOH)2, Sr(OH)2, and Ca(OH)2 are marginally soluble hydroxides. Calculate the pH of a saturated solution of each of these marginally soluble hydroxides.

Interpretation Introduction

Interpretation:

The pH of a saturated solution of the given hydroxides is to be calculated.

Concept introduction:

The pH of a solution is defined as a figure that expresses the acidity of the alkalinity of a given solution.

The pH of a solution is calculated by the formula, pH=log[H+]

The sum, pH+pOH=14

Explanation

To determine: The pH of a saturated solution of the given hydroxides.

pH of a saturated solution of Ba(OH)2

Concentration of hydroxide ion of Ba(OH)2

The Ksp of Ba(OH)2 is 5.0×103 .

The dissociation reaction of Ba(OH)2 is,

Ba(OH)2Ba2++2OH

The solubility of Ba2+ is assumed to be smol/L .

The solubility product of dissociation of Ba(OH)2 is calculated by the formula,

Ksp=[Ba2+][OH]2

The solubility of Ba(OH)2 can be calculated from the concentration of its ions at equilibrium.

It is assumed that smol/L of solid is dissolved to reach the equilibrium. The meaning of 1:2 stoichiometry of salt is,

smol/LBa(OH)2smol/LBa2++2smol/LOH

Formula

The solubility product of Ba(OH)2 is calculated as,

Ksp=[Ba2+][OH]2=(s)(2s)2=4s3

Where,

  • Ksp is solubility product.
  • [Ba2+] is concentration of Ba2+ .
  • [OH] is concentration of OH .
  • s is the solubility.

Substitute the given value of Ksp in the above expression.

4s3=5.0×103s=0.11mol/L

The [OH] =2s=2(0.11mol/L)=0.22mol/L_

pH Calculation:

The [OH] is 0.22mol/L .

The pOH is calculated by the formula,

pOH=log[OH]

Substitute the value of [OH] in the above expression.

pOH=log[0.22]=0.66

The pH for the solution is =14pOH=140.66=13.34_

The pH of a saturated solution of Ba(OH)2 is 13.34_ .

pH of a saturated solution of Sr(OH)2

Concentration of hydroxide ion of Sr(OH)2

The Ksp of Sr(OH)2 is 3.2×104 .

The dissociation reaction of Sr(OH)2 is,

Sr(OH)2Sr2++2OH

The solubility of Sr2+ is assumed to be smol/L .

The solubility product of dissociation of Sr(OH)2 is calculated by the formula,

Ksp=[Sr2+][OH]2

The solubility of Ba(OH)2 can be calculated from the concentration of its ions at equilibrium.

It is assumed that smol/L of solid is dissolved to reach the equilibrium. The meaning of 1:2 stoichiometry of salt is,

smol/LSr(OH)2smol/LSr2++2smol/LOH

Formula

The solubility product of Sr(OH)2 is calculated as,

Ksp=[Sr2+][OH]2=(s)(2s)2=4s3

Where,

  • Ksp is solubility product

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Additional Science Solutions

Find more solutions based on key concepts

Show solutions add

To temporarily increase the bodys water content, a person need only. a. consume extra salt. b. consume extra su...

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

What gives amino acids their individual properties?

Biology: The Dynamic Science (MindTap Course List)

9-28 Complete the following nuclear reactions. (a) (b) (c) (d) (e)

Introduction to General, Organic and Biochemistry

The current in a 90.0-mH inductor changes with time as i = 1.00t2 6.00t, where i is in amperes and t is in sec...

Physics for Scientists and Engineers, Technology Update (No access codes included)

Describe diffusion in terms or entropy.

Biology: The Unity and Diversity of Life (MindTap Course List)