Biology
5th Edition
ISBN: 9781260487947
Author: BROOKER
Publisher: MCG
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Chapter 17, Problem 10TY
Summary Introduction
Introduction: Genetic disorder are caused due to abnormalities in the genome of a person and these disorders are inheritable from the parents to the offspring. Genetic disorders can be autosomal dominant, autosomal recessive, X-linked dominant, X-linked recessive, Y linked, and mitochondrial disorders. For understanding the inheritance of human genetic diseases “Pedigree analysis” is considered the most effective tool and it follows simple Mendelian pattern.
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Heterozygous is when...
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Chapter 17 Solutions
Biology
Ch. 17.1 - Prob. 1CCCh. 17.1 - Prob. 2CCCh. 17.1 - Prob. 3CCCh. 17.1 - Prob. 4CCCh. 17.1 - Mendels Laws of Inheritance Concept Check: What...Ch. 17.2 - Prob. 1CSCh. 17.2 - Prob. 2CSCh. 17.2 - Prob. 1CCCh. 17.3 - Prob. 1CCCh. 17.3 - Prob. 2CC
Ch. 17.4 - Prob. 1CCCh. 17.4 - Prob. 1EQCh. 17.4 - Prob. 2EQCh. 17.4 - Prob. 3EQCh. 17.5 - Prob. 1CSCh. 17.5 - Prob. 1CCCh. 17.6 - Prob. 1CCCh. 17 - Prob. 1TYCh. 17 - During which phase of nuclear division does the...Ch. 17 - Prob. 3TYCh. 17 - Which of Mendels laws cannot be observed in a...Ch. 17 - During a __________blank, an individual with the...Ch. 17 - Prob. 6TYCh. 17 - Prob. 7TYCh. 17 - A hypothetical flowering plant species produces...Ch. 17 - Genes located on a sex chromosome are said to be...Ch. 17 - Prob. 10TYCh. 17 - Prob. 1CQCh. 17 - A cross is made between individuals having the...Ch. 17 - Core Concept: Systems We can view life as a...Ch. 17 - Discuss the principles of the chromosome theory of...Ch. 17 - When examining a human pedigree, what patterns do...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Is it possible for a bald man and a nonbald woman to have a nonbald son and bald daughter? A. Yes, if the father is homozygous and the mother is heterozygous. B. Yes, if both parents are heterozygous. C. No, it is not possible. D. Yes, if the father is heterozygous and the mother is homozygous.arrow_forwardwhat types of alleles did the parents likely have, to produce the following offspring. The trait is black fur dominated to white fur A. 30 white offspring and 87 black offspring B. 29 white offspring and 32 black offspring C. 25 white offspring D. 55 black offspringarrow_forwardHemochromatosis is an inherited disease caused by a recessive allele. If a woman and her husband, who are both carriers, have three children,what is the probability of each of the following? (a) All three children are of normal phenotype. (b) One or more of the three children have the disease. (c) All three children have the disease. (d) At least one child is phenotypically normal.arrow_forward
- Two parents learn they are each carriers for Cystic Fibrosis, each having the genotype (Aa). Using a punnett square, perform a genetic cross to determine the probability that their children will inherit two recessive alleles and have Cystic Fibrosis (aa). In your answer, explain the probability using either percentages (%) or odds out of 4 (1/4, 3/4, etc).arrow_forwardA cross between a horse homozygous for red hair and a horse homozygous for white hair results in offspring with the coat colour called roan. When you look at the fur of the roan offspring you see both red and white hairs. What type of inheritance best explains this? a) blending inheritance b)codominance c)incomplete codominance d)multiple allelesarrow_forwardA recessive trait will be observed in individuals that are ________ for that trait. a. heterozygous b. homozygous or heterozygous c. homozygous d. diploidarrow_forward
- What is the reason for doing a test cross? a. to identify heterozygous individuals with the dominant phenotype b. to determine which allele is dominant and which is recessive c. to identify homozygous recessive individuals in the F2 d. to determine if two genes assort independentlyarrow_forwardAssume that the ratio of females to males is 1:1. A couple already has two daughters and no sons. If they plan to have a total of six children, what is the probability that they will have four more girls? (a) (b) (c) 116 (d) 132 (e) 164arrow_forwardAlleles for Tay-Sachs disease are inherited in an autosomal recessive pattern. Why would two parents with a normal phenotype have a child with Tay-Sachs? a. Both parents are homozygous for a Tay-Sachs allele. b. Both parents are heterozygous for a Tay-Sachs allele. c. New mutations gave rise to Tay-Sachs in the child. d. b or carrow_forward
- One gene that affects three traits is an example of ________. a. dominance c. pleiotropy b. codominance d. epistasisarrow_forwardIn a family of seven children, a.what is the probability of having 4 boys and 3 girls? b.1 boy and 6 girls? c. All boys?arrow_forwardA woman with a rare autosomal recessive disorder was told that it was unlikely that her children would have the disorderas her husband did not have it. However, her first child has the disorder. a. What is the most likely explanation? b. Diagram the cross between the woman and her husband using a Punnett square, give the genotypic ratio (GR) and phenotypic ratio (PR) from the Punnett square. c. Based on the Punnett square results, what is the chance that her next child will have the disorder?arrow_forward
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