Organic Chemistry - Standalone book
10th Edition
ISBN: 9780073511214
Author: Francis A Carey Dr., Robert M. Giuliano
Publisher: McGraw-Hill Education
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Chapter 17, Problem 31P
Interpretation Introduction
Interpretation:
The relationship between two compounds that are formed by the oxidation of
Concept introduction:
The replacement or substitution of one functional group with another different functional group in any
In nucleophilic substitution reaction, nucleophile takes the position of leaving group by attacking on the electron deficient carbon atom.
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Describe the ozonolysis of alkenes
one mole of a hydrocarbon(A) reacts with one mole of beomine giving a dibromo compound C5H10Br2.Substance A on treatment with cold dilute kMnO4 solution forms a compound C5C12O2(C5H12O2) on ozonolysis A,gives equimolar quantities of propanone and ethanol.Deduce the structure of substance A.
1.Describe the ozonolysis of alkenes
2.one mole of a hydrocarbon(A) reacts with one mole of beomine giving a dibromo compound C5H10Br2.Substance A on treatment with cold dilute kMnO4 solution forms a compound C5C12O2(C5H12O2) on ozonolysis A,gives equimolar quantities of propanone and ethanol.Deduce the structure of substance A.
Compound A (C9H12) absorbs three equivalents of H2 on a Catalina reduction over a palladium catalyst to give propylcyclohexane. On ozonolysis, compound A give the two products shown below. On treatment with NH2 , NH3 followed by addition of 1_bromo4methylpentane, compound A gave a new hydrocarbon,B (c5H24 ). What are the structures of compound A and B?
Chapter 17 Solutions
Organic Chemistry - Standalone book
Ch. 17.1 - Prob. 1PCh. 17.2 - The heats of combustion of 1, 2-epoxybutane...Ch. 17.3 - Prob. 3PCh. 17.4 - Prob. 4PCh. 17.5 - Prob. 5PCh. 17.6 - Problem 17.6 (a) Write equations describing two...Ch. 17.6 - Problem 17.7 Only one combination of alkyl halide...Ch. 17.6 - Prob. 8PCh. 17.8 - Prob. 9PCh. 17.8 - Prob. 10P
Ch. 17.9 - Prob. 11PCh. 17.10 - Problem 17.12 Classify the bromohydrins formed...Ch. 17.11 - Prob. 13PCh. 17.11 - Prob. 14PCh. 17.12 - Prob. 15PCh. 17.12 - Prob. 16PCh. 17.14 - Prob. 17PCh. 17.15 - Prob. 18PCh. 17.16 - Prob. 19PCh. 17.17 - Problem 17.20 There is another oxygen-stabilized...Ch. 17 - Prob. 21PCh. 17 - Many ethers, including diethyl ether, are...Ch. 17 - Although epoxides are always considered to have...Ch. 17 - The name of the parent six-membered...Ch. 17 - Prob. 25PCh. 17 - Prob. 26PCh. 17 - Prob. 27PCh. 17 - Prob. 28PCh. 17 - Prob. 29PCh. 17 - Given that: does the product of the analogous...Ch. 17 - Prob. 31PCh. 17 - Prob. 32PCh. 17 - Prob. 33PCh. 17 - Prob. 34PCh. 17 - Prob. 35PCh. 17 - Prob. 36PCh. 17 - When (R)-(+)-2-phenyl-2-butanol is allowed to...Ch. 17 - Prob. 38PCh. 17 - Prob. 39PCh. 17 - Write a mechanism for the following reaction.Ch. 17 - Prob. 41PCh. 17 - Prob. 42PCh. 17 - Prob. 43PCh. 17 - Prob. 44PCh. 17 - Prob. 45PCh. 17 - Prob. 46DSPCh. 17 - Prob. 47DSPCh. 17 - Prob. 48DSPCh. 17 - Prob. 49DSPCh. 17 - Epoxide Rearrangements and the NIH Shift This...Ch. 17 - Epoxide Rearrangements and the NIH Shift This...
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- The sex attractant of the housefly has the formula C23 H46. When treated with warm potassium permanganate, this phero- mone gives two products: CH3(CH2)12COOH and CH3(CH2)7COOH. Suggest a structure for this sex attractant. Explain which part of the structure is uncertain.arrow_forwardTwo isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H2O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. Which of the following isomeric pairs best match this data?arrow_forwardTwo isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H2O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. What is the isometric pair of A and B that corresponds?arrow_forward
- Reaction of N,N-diethyl-p-diaminobenzene with sodium nitrite and hydrochloric acid at 0°C and subsequent reaction with nitrobenzene.arrow_forward7. Compound AA, C4H8O, gives a positive result (formation of a silver mirror) when reacted with Tollen’s reagent. Reduction of compound AA with lithium aluminium hydride, LiAlH4 followed by acidified water, H3O+ produces an alcohol, BB. Oxidation of BB with hot acidified potassium dichromate, K2Cr2O7 gives butanoic acid, C3H7COOH. Esterification between butanoic acid and methanol, CH3OH produces compound CC. Dehydration of compound BB using concentrated sulphuric acid, H2SO4 at a temperature of 180°C produces compound DD. Draw the structural formula of compounds AA, BB, CC, and DDarrow_forward1. Compound A, C9H12, absorbs 3 equivalents of H2 on catalytic hydrogenation over palladium catalyst to give B, C9H18. On the treatment with acidic KMnO4, compound A gives among other things, a ketone that was identified as cyclohexanone. On reaction with NaNH2 in NH3, followed by addition of iodomethane, compound A gives a new hydrocarbon C, C10H14. What are the structures of A , B and C?arrow_forward
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- Stearolic acid, C18H32O2, yields stearic acid on catalytic hydrogenation and undergoes oxidative cleavage with ozone to yield nonanoic acid and nonanedioic acid. What is the structure of stearolic acid?arrow_forwardCompound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr) which reacts violently with D2O to give 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (Ch3COCH3) followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which reacts with 2 equivalents of Br2 to give F (C10H16Br4). E undergoes hydrogenation with excess H2 and Pt catalyst to give 2-methylpropylcyclohexane. Determine the structures of compounds A through F, and show your reasoning throughout.arrow_forwardHydrocarbon A, C10H14, has a UV absorption maximum at 236 nm and gives hydrocarbon B, C10H18, on catalytic hydrogenation. A reacts with maleic anhydride to yield a Diels-Alder adduct. Ozonolysis of A followed by zinc/acetic acid treatment yields the following diketo dialdehyde: Propose a structure for hydrocarbon Aarrow_forward
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