
Concept explainers
Epoxide Rearrangements and the NIH Shift
This passage is about two seemingly unrelated aspects of
epoxide rearrangements
arene oxides
These two topics merge in an important biological transformation in which neither the
reactant nor the product is an epoxide
Epoxide rearrangements
In some epoxide ring-opening reactions
As positive charge develops on the ring carbon, one of the groups on the adjacent carbon migrates to it. This migration is assisted by electron
all of this occurs in the same transition state. Subsequent deprotonation gives an
Overall, the reaction resembles the pinacol rearrangement of vicinal
Descriptive Passage and Interpretive Problems) and takes place under similar conditions.
Arene Oxides
Aromatic rings are normally inert to the customary reagents that convert
arene oxides have been synthesized in the laboratory, often by indirect methods. Their chemical
reactivity resembles that of other epoxides.
The most striking thing about arene oxides is their involvement in biological processes. Enzymes
In the liver oxidize
The NIH shift
Although hydroxylation of phenylalanine to tyrosine looks like a typical electrophilic aromatic sub stitution, scientists at the U.S. National Institutes of Health discovered that the biochemical pathway combines epoxidation of the benzene ring followed by epoxide ring opening with rearrangement. This rearrangement, which is the biochemical analog of the pinacol
Acetanilide, which has pain-relieving properties, undergoes a biochemical oxidation
similar to that of the NIH shift that occurs with phenylalanine. The product formed from
acetanilide is itself a pain reliever. What is the structure of this substance (better known as
Tylenol)?

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Chapter 17 Solutions
Organic Chemistry - Standalone book
- please draw out the mechanism to get to the next steparrow_forwardDraw the curved arrow mechanism for the following transformationarrow_forward17. Balance the following equation occurring in an acidic aqueous solution. Show all steps relating to the balancing method. ASH3 + Zn2+ → H3ASO4 + Znarrow_forward
- Which solvent is polar aprotic?arrow_forward12. Two half cells, one containing Fe²* and Fe and the other containing Ag* and Ag, are connected to form a voltaic cell. Use the reference sheet of reduction potentials to determine the value of E°. Is this a spontaneous reaction?arrow_forward7. The standard reduction potentials for two half-reactions are shown above. Which of the statements listed below will be true for the following reaction taking place under standard conditions? a. E° b. E° c. E° = d. E° e. E° = Al (s) + Cr³+ →> Al3+ + Cr (s) 0.93 V, and the reaction is not spontaneous 0.93 V, and the reaction is spontaneous 2.39 V, and the reaction is not spontaneous 2.39 V, and the reaction is not spontaneous 0.93 V, and the reaction is spontaneous Cu2+ + 2e Zn2+ + 2e → Cu E° = +0.34 V → Zn E° = -0.76 V E° = -1.18 V Mn2+ + 2e → Mn 8. Based on the above reduction potential, which of the following reactions will occur spontaneously? a. Mn²+ + Cu → Mn + Cu²+ b. Mn²+ + Zn c. Zn²+ + Cu → Mn + Zn2+ Zn + Cu2+ d. Zn²+ + Mn → Zn + Mn²+ e. Cu2++Zn2+ → Cu + Zn 9. The redox reaction H+ + N₂ →> NH4+ + N is a. correctly balanced b. correctly balanced for number of atoms but not for charge c. correctly balanced for charge but not for number of atoms d. not balanced for number of…arrow_forward
- Pls help me on allarrow_forward13. Write the oxidation half reaction, the reduction half reaction, and the overall cell reaction for the following galvanic cell. Identify the anode and the cathode and state why you labeled the metals that way. Zn (s) | Zn2+ (aq) (aq) Cu2+ | Cu (s)arrow_forwardPls help me on allarrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning

