Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
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Chapter 18, Problem 18.42SP
Using the AISC column equations, select the lightest W10 shape for a column subjected to an axial compressive load of 280 kips. The unbraced length of the column is 18 ft and the ends are pinned. The steel is ASTM A992.
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Determine the critical load for a pinned-end column made of a circular bar of AISI1020 hot-rolled steel. The diameter of the bar is 20 mm, and its length is 800 mm.
(a) Explain FIVE (5) factors that may influence the optimum column design under an axial compressive load.
(b) A 3.6 m long pin-ended column is formed from an A-36 steel circular hollow section with an outer diameter of 75 mm. Determine the minimum thickness, t (to the nearest integer in mm) of the circular hollow section so that the column can safely support the load of 200 kN without buckling. If the outer diameter of the steel circular hollow section is reduced to 62 mm and the ends are pinned-fixed supported, analyse whether the column with the same applied load and the sectional thickness computed above will cause a buckling failure.
The column in Fig. is made of aluminum alloy 2014-T6 and is used tosupport an eccentric load P. Determine the maximum allowable value of Pthat can be supported if the column is fixed at its base and free at its top.
Chapter 18 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 18 - Calculate the Euler buckling load for an axially...Ch. 18 - Calculate the Euler buckling load for a...Ch. 18 - A pin-connected axially loaded compression member...Ch. 18 - Prob. 18.4PCh. 18 - Plot a curve showing the relationship of feversus...Ch. 18 - A W1222 structural steel wide-flange section is...Ch. 18 - Prob. 18.7PCh. 18 - Calculate the allowable axial compressive load for...Ch. 18 - A W20059 structural steel wide-flange section is...Ch. 18 - Use Euler’s formula and a factor of safety of 2.5...
Ch. 18 - For Problems 18.11 through 18.17, unless otherwise...Ch. 18 - For Problems 18.11 through 18.17, unless otherwise...Ch. 18 - For Problems 18.11 through 18.17, unless otherwise...Ch. 18 - For Problems 18.11 through 18.17, unless otherwise...Ch. 18 - For Problems 18.11 through 18.17, unless otherwise...Ch. 18 - For Problems 18.11 through 18.17, unless otherwise...Ch. 18 - Prob. 18.17PCh. 18 - For Problems 18.18 through 18.21, use the...Ch. 18 - For Problems 18.18 through 18.21, use the...Ch. 18 - For Problems 18.18 through 18.21, use the...Ch. 18 - For Problems 18.18 through 18.21, use the...Ch. 18 - For Problems 18.22 through 18.26, assume normal...Ch. 18 - For Problems 18.22 through 18.26, assume normal...Ch. 18 - For Problems 18.22 through 18.26 assume normal...Ch. 18 - For Problems 18.22 through 18.26, assume normal...Ch. 18 - For Problems 18.22 through 18.26, assume normal...Ch. 18 - For the following computer problems, any...Ch. 18 - For the following computer problems, any...Ch. 18 - Calculate the Euler buckling load for an axially...Ch. 18 - 18.32 Calculate the Euler buckling load for an...Ch. 18 - 18.33 A structural steel shape of ASTM A992 steel...Ch. 18 - Calculate the Euler buckling load for a...Ch. 18 - 18.35 Rework Problem 18.34 assuming that the...Ch. 18 - 18.36 A built-up steel column is made by welding a...Ch. 18 - A 2-in-diameter standard-weight steel pipe is used...Ch. 18 - A structural steel column is 30 ft long and must...Ch. 18 - 18.39 Compute the allowable axial compressive load...Ch. 18 - 18.40 Determine the allowable axial compressive...Ch. 18 - 18.41 Using the AISC column approach, compute the...Ch. 18 - Using the AISC column equations, select the...Ch. 18 - Select the lightest extrastrong steel pipe section...Ch. 18 - 18.44 Compute the required diameter of a steel...Ch. 18 - 18.45 A 19-mm-diameter steel rod is 350 mm in...Ch. 18 - 18.46 A pin-connected linkage bar is 16 in. long...Ch. 18 - Prob. 18.47SPCh. 18 - Prob. 18.48SPCh. 18 - Prob. 18.49SPCh. 18 - Prob. 18.50SPCh. 18 - Prob. 18.51SP
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- A circular-cross-section bar with a diameter of 50mm and a length of 1.25 m is axially loaded. The baris made of medium-carbon steel. Both ends are pinned.Determine(a) Whether the Johnson or the Euler formula shouldbe used.(b) The critical load.arrow_forwardA bar having a length of 30 in. is used to support an axial compressive loadof 12 kip, Fig. It is pin supported at its ends and made of a 2014-T6 aluminum alloy. Determine the dimensions of its cross-sectional area if its width is to be twice its thickness.arrow_forwardDetermine if the following column is long or short, and then determine the critical load on a steel column having a rectangular cross-section, 12mm by 18mm and length of 250 mm. it is fixed on both ends and made from a steel that has the following properties: E=209 Gpa and Sy=290 Mpa. What is the Slenderness ratio, The Cc, The long or short column, The critical load.arrow_forward
- Determine the ratio of buckling strengths of two columns of circular cross-section, one hollow and other solid when both are made of same material, have same length, cross-sectional area and end conditions. The internal diameter of the hollow column is half of its external diameter.arrow_forwardFor a rod made of aluminum alloy 2014-T6, select the smallest square cross section that can be used if the rod is to carry a 55-kip centric load.arrow_forwardVerify the adequacy of column AB, part of a sway frame structure, to carry the loads shown in the figure. The column is made of ASTM A992 steel (Fy = 50 ksi). Use ASD specifications. For determining its effective length factors, neglect inelastic effect.arrow_forward
- A column consists of a 2.5 m long hollow tube with an outside diameter equal to 1.5 times that of the inside diameter. The column must carry an axial load of 40 KN without buckling. Use a factor of safety of 5 and calculate the dimensions of the tube if one end is fixed and the other end is free. Use the Euler formula and take ?=200 ???.arrow_forwardA hollow, short compression member, of normalized cast steel (ASTM A27-58, 65 ksi), is to support a load of 1500 kips with a factor of safety of 8 based on the ultimate strength. Determine the outside and inside diameters if Do = 2Diarrow_forwardA 5 ft column is made from 2024-T4 Aluminum. Column has a square cross section of 2 in x 2 in. Both ends of the column are pinned. Calculate the critical load (Pcr). Note: I am having trouble understanding what the Module of Elasticity is for 2024-T4 Aluminum.arrow_forward
- Question no 1: a)Determine the critical load for its stability if Both ends are fixed.b) For these systems determine the developed stress (It is pin supported, bottom is fixed and the top is pinned;The system is fixed on the bottom ,Both ends are fixed.) The length LB is 14m and material is ANSI1020 where beam is W12 X 87.arrow_forwardDiscuss what is meant by buckling for a long slender bar. Discuss the difference of a pin supported column in comparison to a fixed supported column. Support your answer with appropriate sketches.arrow_forwardCompute the internal diameter of the 10 m length hollow cast iron column. If the externaldiameter is two times the internal diameter and the safe compressive load on a hollowcast iron column with one end rigidly fixed and other end hinged is 60 kN. Use Euler’sformula with a factor of safety of 3 and E = 90 kN/mm2arrow_forward
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Column buckling; Author: Amber Book;https://www.youtube.com/watch?v=AvvaCi_Nn94;License: Standard Youtube License