Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
1st Edition
ISBN: 9780078945830
Author: Charles William McLaughlin, Marilyn Thompson, Dinah Zike
Publisher: Glencoe Mcgraw-Hill
Question
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Chapter 18, Problem 4STP
To determine

To Choose: The correct statement.

Expert Solution & Answer
Check Mark

Answer to Problem 4STP

The correct option is (B).

Explanation of Solution

Given:

The given diagram is

Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education), Chapter 18, Problem 4STP

Calculation:

The covalent bond is formed by the sharing of electrons between 2 non-metals. The figure shows the presence of hydrogen and fluorine. As both are non-metals and share the electrons with each other to form the covalent bond.

The atomic number of hydrogen is 1 and fluorine is 9.

Hydrogen requires 1 electron to complete its outermost shell. Fluorine has 7 valence electrons and fluorine requires 1 electron to get the noble gas configuration.

Therefore, both hydrogen and fluorine atoms require 1 electron each to complete their outermost shell, so there is equal sharing of electrons between hydrogen and fluorine. Thus, the bond between hydrogen and fluorine requires equal sharing of electrons.

Conclusion:

Hence, the electrons are shared equally in the bonds of this molecule.

Chapter 18 Solutions

Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)

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