menu
bartleby
search
close search
Hit Return to see all results
Subscribe
Sign in
Subjects
Business
Accounting
Economics
Finance
Leadership
Management
Marketing
Operations Management
Engineering
Bioengineering
Chemical Engineering
Civil Engineering
Computer Engineering
Computer Science
Electrical Engineering
Mechanical Engineering
Math
Advanced Math
Algebra
Calculus
Geometry
Probability
Statistics
Trigonometry
Science
Advanced Physics
Biochemistry
Biology
Chemistry
Earth Science
Health & Nutrition
Nursing
Physics
Social Science
Anthropology
Psychology
Sociology

Science
ChemistryOrganic And Biological Chemistry7th Edition

close solutoin list
Chapter 2, Problem 2.12EP
BuyFindarrow_forward

Organic And Biological Chemistry

7th Edition
STOKER + 1 other
ISBN: 9781305081079

Solutions

Chapter
Section
Problem 2.1EP
Problem 2.2EP
Problem 2.3EP
Problem 2.4EP
Problem 2.5EP
Problem 2.6EP
Problem 2.7EP
Problem 2.8EP
Problem 2.9EP
Problem 2.10EP
Problem 2.11EP
Problem 2.12EP
Problem 2.13EP
Problem 2.14EP
Problem 2.15EP
Problem 2.16EP
Problem 2.17EP
Problem 2.18EP
Problem 2.19EP
Problem 2.20EP
Problem 2.21EP
Problem 2.22EP
Problem 2.23EP
Problem 2.24EP
Problem 2.25EP
Problem 2.26EP
Problem 2.27EP
Problem 2.28EP
Problem 2.29EP
Problem 2.30EP
Problem 2.31EP
Problem 2.32EP
Problem 2.33EP
Problem 2.34EP
Problem 2.35EP
Problem 2.36EP
Problem 2.37EP
Problem 2.38EP
Problem 2.39EP
Problem 2.40EP
Problem 2.41EP
Problem 2.42EP
Problem 2.43EP
Problem 2.44EP
Problem 2.45EP
Problem 2.46EP
Problem 2.47EP
Problem 2.48EP
Problem 2.49EP
Problem 2.50EP
Problem 2.51EP
Problem 2.52EP
Problem 2.53EP
Problem 2.54EP
Problem 2.55EP
Problem 2.56EP
Problem 2.57EP
Problem 2.58EP
Problem 2.59EP
Problem 2.60EP
Problem 2.61EP
Problem 2.62EP
Problem 2.63EP
Problem 2.64EP
Problem 2.65EP
Problem 2.66EP
Problem 2.67EP
Problem 2.68EP
Problem 2.69EP
Problem 2.70EP
Problem 2.71EP
Problem 2.72EP
Problem 2.73EP
Problem 2.74EP
Problem 2.75EP
Problem 2.76EP
Problem 2.77EP
Problem 2.78EP
Problem 2.79EP
Problem 2.80EP
Problem 2.81EP
Problem 2.82EP
Problem 2.83EP
Problem 2.84EP
Problem 2.85EP
Problem 2.86EP
Problem 2.87EP
Problem 2.88EP
Problem 2.89EP
Problem 2.90EP
Problem 2.91EP
Problem 2.92EP
Problem 2.93EP
Problem 2.94EP
Problem 2.95EP
Problem 2.96EP
Problem 2.97EP
Problem 2.98EP
Problem 2.99EP
Problem 2.100EP
Problem 2.101EP
Problem 2.102EP
Problem 2.103EP
Problem 2.104EP
Problem 2.105EP
Problem 2.106EP
Problem 2.107EP
Problem 2.108EP
Problem 2.109EP
Problem 2.110EP
Problem 2.111EP
Problem 2.112EP
Problem 2.113EP
Problem 2.114EP
Problem 2.115EP
Problem 2.116EP
Problem 2.117EP
Problem 2.118EP
Problem 2.119EP
Problem 2.120EP
Problem 2.121EP
Problem 2.122EP
Problem 2.123EP
Problem 2.124EP
Problem 2.125EP
Problem 2.126EP
Problem 2.127EP
Problem 2.128EP
Problem 2.129EP
Problem 2.130EP
BuyFindarrow_forward

Organic And Biological Chemistry

7th Edition
STOKER + 1 other
ISBN: 9781305081079
Textbook Problem

Indicate whether each of the following molecular formulas for hydrocarbons is that for an alkene with one double bond or a cycloalkene with one double bond?

  1. a. C4H8
  2. b. C5H8
  3. c. C6H10
  4. d. C5H10

(a)

Interpretation Introduction

Interpretation:

The given molecular formula belongs to alkene with one double bond, or a cycloalkene with one double bond has to be indicated.

Concept Introduction:

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Saturated hydrocarbons are alkanes.  Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.

Alkane has general molecular formula as CnH2n+2.  Alkene in which one double is present has general molecular formula as CnH2n.  Alkyne in which one triple bond is present has the general molecular formula as CnH2n-2.  Cycloalkanes have the general molecular formula as CnH2n.  Cycloalkenes in which one double bond is present have the general molecular formula as CnH2n-2.

Explanation

Given molecular formula is C4H8.  Considering the general molecular formula the value of “n” is 4.  The total number of hydrogen atoms present in the given molecular formula is 8.  This is twice the number of carbon atoms

(b)

Interpretation Introduction

Interpretation:

The given molecular formula belongs to alkene with one double bond, or a cycloalkene with one double bond has to be indicated.

Concept Introduction:

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Saturated hydrocarbons are alkanes.  Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.

Alkane has general molecular formula as CnH2n+2.  Alkene in which one double is present has general molecular formula as CnH2n.  Alkyne in which one triple bond is present has the general molecular formula as CnH2n-2.  Cycloalkanes have the general molecular formula as CnH2n.  Cycloalkenes in which one double bond is present have the general molecular formula as CnH2n-2.

(c)

Interpretation Introduction

Interpretation:

The given molecular formula belongs to alkene with one double bond, or a cycloalkene with one double bond has to be indicated.

Concept Introduction:

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Saturated hydrocarbons are alkanes.  Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.

Alkane has general molecular formula as CnH2n+2.  Alkene in which one double is present has general molecular formula as CnH2n.  Alkyne in which one triple bond is present has the general molecular formula as CnH2n-2.  Cycloalkanes have the general molecular formula as CnH2n.  Cycloalkenes in which one double bond is present have the general molecular formula as CnH2n-2.

(d)

Interpretation Introduction

Interpretation:

The given molecular formula belongs to alkene with one double bond, or a cycloalkene with one double bond has to be indicated.

Concept Introduction:

Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms.  Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements.  The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.

Hydrocarbons are further classified into two categories.  They are saturated hydrocarbons and unsaturated hydrocarbons.  The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon.  The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.

Saturated hydrocarbons are alkanes.  Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.

Alkane has general molecular formula as CnH2n+2.  Alkene in which one double is present has general molecular formula as CnH2n.  Alkyne in which one triple bond is present has the general molecular formula as CnH2n-2.  Cycloalkanes have the general molecular formula as CnH2n.  Cycloalkenes in which one double bond is present have the general molecular formula as CnH2n-2.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution
arrow_back
Chapter 2,
Problem 2.11EP
Chapter 2,
Problem 2.13EP
arrow_forward

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Chapter 2 Solutions

Show all chapter solutions add
Sect-2.1 P-1QQSect-2.1 P-2QQSect-2.1 P-3QQSect-2.2 P-1QQSect-2.2 P-2QQSect-2.2 P-3QQSect-2.2 P-4QQSect-2.3 P-1QQSect-2.3 P-2QQSect-2.3 P-3QQ
Sect-2.3 P-4QQSect-2.4 P-1QQSect-2.4 P-2QQSect-2.5 P-1QQSect-2.5 P-2QQSect-2.5 P-3QQSect-2.6 P-1QQSect-2.6 P-2QQSect-2.6 P-3QQSect-2.7 P-1QQSect-2.7 P-2QQSect-2.7 P-3QQSect-2.8 P-1QQSect-2.8 P-2QQSect-2.9 P-1QQSect-2.9 P-2QQSect-2.10 P-1QQSect-2.10 P-2QQSect-2.10 P-3QQSect-2.10 P-4QQSect-2.10 P-5QQSect-2.11 P-1QQSect-2.11 P-2QQSect-2.11 P-3QQSect-2.11 P-4QQSect-2.11 P-5QQSect-2.12 P-1QQSect-2.12 P-2QQSect-2.12 P-3QQSect-2.12 P-4QQSect-2.12 P-5QQSect-2.13 P-1QQSect-2.13 P-2QQSect-2.13 P-3QQSect-2.14 P-1QQSect-2.14 P-2QQSect-2.14 P-3QQSect-2.14 P-4QQSect-2.15 P-1QQSect-2.15 P-2QQSect-2.15 P-3QQSect-2.15 P-4QQSect-2.16 P-1QQSect-2.16 P-2QQCh-2 P-2.1EPCh-2 P-2.2EPCh-2 P-2.3EPCh-2 P-2.4EPCh-2 P-2.5EPCh-2 P-2.6EPCh-2 P-2.7EPCh-2 P-2.8EPCh-2 P-2.9EPCh-2 P-2.10EPCh-2 P-2.11EPCh-2 P-2.12EPCh-2 P-2.13EPCh-2 P-2.14EPCh-2 P-2.15EPCh-2 P-2.16EPCh-2 P-2.17EPCh-2 P-2.18EPCh-2 P-2.19EPCh-2 P-2.20EPCh-2 P-2.21EPCh-2 P-2.22EPCh-2 P-2.23EPCh-2 P-2.24EPCh-2 P-2.25EPCh-2 P-2.26EPCh-2 P-2.27EPCh-2 P-2.28EPCh-2 P-2.29EPCh-2 P-2.30EPCh-2 P-2.31EPCh-2 P-2.32EPCh-2 P-2.33EPCh-2 P-2.34EPCh-2 P-2.35EPCh-2 P-2.36EPCh-2 P-2.37EPCh-2 P-2.38EPCh-2 P-2.39EPCh-2 P-2.40EPCh-2 P-2.41EPCh-2 P-2.42EPCh-2 P-2.43EPCh-2 P-2.44EPCh-2 P-2.45EPCh-2 P-2.46EPCh-2 P-2.47EPCh-2 P-2.48EPCh-2 P-2.49EPCh-2 P-2.50EPCh-2 P-2.51EPCh-2 P-2.52EPCh-2 P-2.53EPCh-2 P-2.54EPCh-2 P-2.55EPCh-2 P-2.56EPCh-2 P-2.57EPCh-2 P-2.58EPCh-2 P-2.59EPCh-2 P-2.60EPCh-2 P-2.61EPCh-2 P-2.62EPCh-2 P-2.63EPCh-2 P-2.64EPCh-2 P-2.65EPCh-2 P-2.66EPCh-2 P-2.67EPCh-2 P-2.68EPCh-2 P-2.69EPCh-2 P-2.70EPCh-2 P-2.71EPCh-2 P-2.72EPCh-2 P-2.73EPCh-2 P-2.74EPCh-2 P-2.75EPCh-2 P-2.76EPCh-2 P-2.77EPCh-2 P-2.78EPCh-2 P-2.79EPCh-2 P-2.80EPCh-2 P-2.81EPCh-2 P-2.82EPCh-2 P-2.83EPCh-2 P-2.84EPCh-2 P-2.85EPCh-2 P-2.86EPCh-2 P-2.87EPCh-2 P-2.88EPCh-2 P-2.89EPCh-2 P-2.90EPCh-2 P-2.91EPCh-2 P-2.92EPCh-2 P-2.93EPCh-2 P-2.94EPCh-2 P-2.95EPCh-2 P-2.96EPCh-2 P-2.97EPCh-2 P-2.98EPCh-2 P-2.99EPCh-2 P-2.100EPCh-2 P-2.101EPCh-2 P-2.102EPCh-2 P-2.103EPCh-2 P-2.104EPCh-2 P-2.105EPCh-2 P-2.106EPCh-2 P-2.107EPCh-2 P-2.108EPCh-2 P-2.109EPCh-2 P-2.110EPCh-2 P-2.111EPCh-2 P-2.112EPCh-2 P-2.113EPCh-2 P-2.114EPCh-2 P-2.115EPCh-2 P-2.116EPCh-2 P-2.117EPCh-2 P-2.118EPCh-2 P-2.119EPCh-2 P-2.120EPCh-2 P-2.121EPCh-2 P-2.122EPCh-2 P-2.123EPCh-2 P-2.124EPCh-2 P-2.125EPCh-2 P-2.126EPCh-2 P-2.127EPCh-2 P-2.128EPCh-2 P-2.129EPCh-2 P-2.130EP

Additional Science Solutions

Find more solutions based on key concepts

Show solutions add

A compound of unknown structure gave the following spectroscopic data: Mass spectrum: M+=88.1 IR: 3600 cm-1 1Η...

Organic Chemistry

Consider the following four titrations (iiv): i. 150 mL of 0.2 M NH3 (Kb = 1.8 105) by 0.2 M HCl ii. 150 mL of...

Chemistry

Use rise web to look up the percentage of dopant for a commercially available p-type semiconductor. Imagine tha...

Chemistry for Engineering Students

49. Think of something from your everyday life about which you are curious. Design an experiment or set of meas...

Chemistry In Focus

Calculate the osmotic pressure of a solution that contains 220.0g of ethylene glycol (C2H6O2), a nonelectrolyte...

Chemistry for Today: General, Organic, and Biochemistry

Write the appropriate symbol in the blank (,,or=). (a) 303 m 303103km (b) 500 g 0.500 kg (c) 1.50 cm3 1.50103nm...

Chemistry: Principles and Reactions

As the bead engineer of your starship in charge of the warp drive, you notice that the supply of dilithium is c...

Chemistry

Distinguish between the terms equilibrium constant and reaction quotient. When Q = K, what does this say about ...

Chemistry: An Atoms First Approach

Derive equation .

Physical Chemistry

Consider the following separations of materials. State whether a physical process or a chemical reaction is inv...

General Chemistry - Standalone book (MindTap Course List)

21. Give the general formula, including the functional group, and draw condensed structural formulas for two ex...

Chemistry In Focus

. Consider 0.25 M solutions of the following salts: NaCl. RbOC1, KI, Ba(ClO4),, and NH4NO3. For each salt, indi...

Introductory Chemistry: A Foundation

Give the symbols for the four metals mentioned in this article.

Chemistry & Chemical Reactivity

2.30 Using Coulomb’s law, explain how the difference between attractive and repulsive interactions between ions...

Chemistry for Engineering Students

You are working at an electronics fabrication shop. Your current project is on the team producing resistors for...

Physics for Scientists and Engineers

Relate four strategies that parents and caregivers can implement to foster healthy eating behaviors starting in...

Nutrition Through the Life Cycle (MindTap Course List)

Coal often contains sulfur (S) as an impurity that is released as gaseous SO2 during combustion, and SO2 is one...

Environmental Science (MindTap Course List)

Why are mathematical results rounded?

An Introduction to Physical Science

Integrated Concepts An ultracentrifuge accelerates from rest to 100,000 rpm in 2.00 min. (a) What is its angula...

College Physics

RECALL Single-stranded regions of DNA are attacked by nucleases in the cell, yet portions of DNA are in a singl...

Biochemistry

Freezing is better than canning tor preserving vitamins in foods. T F

Nutrition

A C3 plant absorbs a carbon radio isotope (aspartof14CO2). In which stable organic compound does the labeled ca...

BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)

A carpet is to be installed in a room of length 9.72 m and width 5.3 m. Find the area of the mom retaining the ...

College Physics

Four hypothetical elements, A, B, C, and D, have electronegativities A = 3.4, B = 3.1, C = 2.5, end D = 1.7. Th...

General, Organic, and Biological Chemistry

Explain why you agree or disagree with the following propositions: a. Stabilizing population is not desirable b...

Environmental Science (MindTap Course List)

After four years of experiencing amenorrhea, Tonya seeks medical care to help her become pregnane. She is convi...

Nutrition Through The Life Cycle

What are the structures and function of anchoring junctions, tight junctions, and gap junctions?

Biology: The Dynamic Science (MindTap Course List)

Human body temperature is about 310 K (3.10 × 102 K, 98.6°F). At what wavelength do humans radiate the most ene...

Horizons: Exploring the Universe (MindTap Course List)

The nutrition of some plants is enhanced by a mutually beneficial interaction between a root and soil bacteria....

Biology: The Unity and Diversity of Life (MindTap Course List)

(Indicates a review question, which means it requires only a basic understanding of the material to answer. Que...

Inquiry into Physics

22-73 Silver nitrate is sometimes put into the eyes of newborn infants as a preventive measure against gonorrhe...

Introduction to General, Organic and Biochemistry

Why might vegetation differ on the windward and leeward sides of an island?

Fundamentals of Physical Geography

Estimate the number of breaths taken by a human being during an average lifetime.

College Physics

A form of learning in which an animal forms a strong attachment to a moving object (usually its parent) within ...

Biology (MindTap Course List)

Explain why (a) calcium ions and (b) ACh are vital for muscle contraction.

Human Biology (MindTap Course List)

Answers to all problems are at the end of this book. Detailed solutions are available in the Student Solutions ...

Biochemistry

Using the food listings in Table 18-10, create a 1-day menu of four meals and snacks that provides about 230 gr...

Understanding Nutrition (MindTap Course List)

The Academy of Nutrition and Dietetics recommends fluoride-free water for the U.S. population. T F

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

We each carry 20,000 genes in our genome. Genes can be patented, and over 6,000 human genes have been patented....

Human Heredity: Principles and Issues (MindTap Course List)

Case 1 As the preload decreases, the cardiac output _____________________.

Cardiopulmonary Anatomy & Physiology

bartleby
© bartleby 2019