ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5
ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5
2nd Edition
ISBN: 9780393664034
Author: KARTY
Publisher: NORTON
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Chapter 2, Problem 2.41P
Interpretation Introduction

(a)

Interpretation:

The polarity of the given molecule is to be determined.

Concept introduction:

The dipole moment of a molecule is a measure of the magnitude of its dipole. A dipole moment is a vector, which has both magnitude and direction. Bond polarity originates from bonds between atoms of different electronegativity. Symmetry of molecules also predicts the polarity of a molecule.

Expert Solution
Check Mark

Answer to Problem 2.41P

The given molecule A is nonpolar.

Explanation of Solution

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 2, Problem 2.41P , additional homework tip  1

The given molecule is in trans form. The directions of the vectors of both the C-F bonds are equal but opposite to each other. Hence the dipole moments of both the C-F bonds get cancelled out with each other. Therefore, there is no net dipole moment.

Conclusion

Dipole moment on this molecule is symmetrically distributed; hence the given molecule A is nonpolar.

Interpretation Introduction

(b)

Interpretation:

The polarity of the given molecule is to be determined.

Concept introduction:

The dipole moment of a molecule is a measure of the magnitude of its dipole. A dipole moment is a vector, which has both magnitude and direction. Bond polarity originates from bonds between atoms of different electronegativity. Symmetry of molecules also predicts the polarity of a molecule.

Expert Solution
Check Mark

Answer to Problem 2.41P

The given molecule B is polar.

Explanation of Solution

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 2, Problem 2.41P , additional homework tip  2

The given molecule is in cis form. The direction of vectors of both the C-F bonds is in the same direction, giving a net permanent dipole moment to the molecule.

Conclusion

Dipole moment on this molecule is not symmetrically distributed; hence the given molecule B is polar.

Interpretation Introduction

(c)

Interpretation:

The polarity of the given molecules is to be determined.

Concept introduction:

The dipole moment of a molecule is a measure of the magnitude of its dipole. A dipole moment is a vector, which has both magnitude and direction. Bond polarity originates from bonds between atoms of different electronegativity. Symmetry of molecules also predicts the polarity of a molecule.

Expert Solution
Check Mark

Answer to Problem 2.41P

Molecule C is nonpolar.

Explanation of Solution

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 2, Problem 2.41P , additional homework tip  3

In this molecule, both the C-Cl bonds are opposite to each other, so the dipole moments are cancelled out with each other. Therefore, there is no net dipole moment in this molecule.

Conclusion

Dipole moment on this molecule is symmetrically distributed; hence the given molecule C is nonpolar.

Interpretation Introduction

(d)

Interpretation:

The polarity of the given molecules is to be determined.

Concept introduction:

The dipole moment of a molecule is a measure of the magnitude of its dipole. A dipole moment is a vector, which has both magnitude and direction. Bond polarity originates from bonds between atoms of different electronegativity. Symmetry of molecules also predicts the polarity of a.

Expert Solution
Check Mark

Answer to Problem 2.41P

The given molecule D is polar.

Explanation of Solution

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 2, Problem 2.41P , additional homework tip  4

In this molecule, chlorine is more electronegative than the carbon atom; hence the direction of the vector of dipole moment is more towards C-Cl bond, giving a net dipole moment to the molecule.

Conclusion

Dipole moment on this molecule is not symmetrically distributed; hence the given molecule D is polar.

Interpretation Introduction

(e)

Interpretation:

The polarity of the given molecules is to be determined.

Concept introduction:

The dipole moment of a molecule is a measure of the magnitude of its dipole. A dipole moment is a vector, which has both magnitude and direction. Bond polarity originates from bonds between atoms of different electronegativity. Symmetry of molecules also predicts the polarity of a molecule.

Expert Solution
Check Mark

Answer to Problem 2.41P

Molecule E is polar.

Explanation of Solution

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 2, Problem 2.41P , additional homework tip  5

In this molecule, Chlorine is more electronegative than bromine; hence the direction of the vector of dipole moment is more towards C-Cl bond, giving a net dipole moment to the molecule.

Conclusion

Dipole moment on this molecule is not symmetrically distributed; hence the given molecule E is polar.

Interpretation Introduction

(f)

Interpretation:

The polarity of the given molecules is to be determined.

Concept introduction:

The dipole moment of a molecule is a measure of the magnitude of its dipole. A dipole moment is a vector, which has both magnitude and direction. Bond polarity originates from bonds between atoms of different electronegativity. Symmetry of molecules also predicts the polarity of a molecule.

Expert Solution
Check Mark

Answer to Problem 2.41P

Molecule F is nonpolar.

Explanation of Solution

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 2, Problem 2.41P , additional homework tip  6

In this molecule, there is no electronegative atom present since no charge separation is taking place. So there is no net dipole moment.

Conclusion

Dipole moment on this molecule is symmetrically distributed; hence the given molecule F is nonpolar.

Interpretation Introduction

(g)

Interpretation:

The polarity of the given molecules is to be determined.

Concept introduction:

The dipole moment of a molecule is a measure of the magnitude of its dipole. A dipole moment is a vector, which has both magnitude and direction. Bond polarity originates from bonds between atoms of different electronegativity. Symmetry of molecules also predicts the polarity of a molecule.

Expert Solution
Check Mark

Answer to Problem 2.41P

Molecule G is polar.

Explanation of Solution

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 2, Problem 2.41P , additional homework tip  7

In this molecule, Chlorine is an electronegative atom, and both the C-Cl bonds are in the same direction. Therefore, the direction of the vector of dipole is moment is upward, giving a net dipole moment to the molecule.

Conclusion

Dipole moment on this molecule is not symmetrically distributed; hence the given molecule G is polar.

Interpretation Introduction

(h)

Interpretation:

The polarity of the given molecules is to be determined.

Concept introduction:

The dipole moment of a molecule is a measure of the magnitude of its dipole. A dipole moment is a vector, which has both magnitude and direction. Bond polarity originates from bonds between atoms of different electronegativity. Symmetry of molecules also predicts the polarity of a molecule.

Expert Solution
Check Mark

Answer to Problem 2.41P

Molecule H is nonpolar.

Explanation of Solution

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 2, Problem 2.41P , additional homework tip  8

In the molecule, chlorine is an electronegative atom, and both the C-Cl bonds are in opposite direction. Therefore, the directions of the vectors of dipole moment of two C-Cl bonds get cancelled out with each other. Hence there is no net dipole moment.

Conclusion

Dipole moment on this molecule is symmetrically distributed; hence the given molecule H is nonpolar.

Interpretation Introduction

(i)

Interpretation:

The polarity of the given molecules is to be determined.

Concept introduction:

The dipole moment of a molecule is a measure of the magnitude of its dipole. A dipole moment is a vector, which has both magnitude and direction. Bond polarity originates from bonds between atoms of different electronegativity. Symmetry of molecules also predicts the polarity of a molecule.

Expert Solution
Check Mark

Answer to Problem 2.41P

Molecule I is polar.

Explanation of Solution

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 2, Problem 2.41P , additional homework tip  9

In this molecule, bromine is an electronegative atom, but one C-Br bond is in upward direction, and two C-Br bonds are in downward direction. Therefore, the net dipole moment acts in downward direction.

Conclusion

Dipole moment on this molecule is not symmetrically distributed; hence the given molecule I is polar.

Interpretation Introduction

(j)

Interpretation:

The polarity of the given molecules is to be determined.

Concept introduction:

The dipole moment of a molecule is a measure of the magnitude of its dipole. A dipole moment is a vector, which has both magnitude and direction. Bond polarity originates from bonds between atoms of different electronegativity. Symmetry of molecules also predicts the polarity of a molecule.

Expert Solution
Check Mark

Answer to Problem 2.41P

Molecule J is polar.

Explanation of Solution

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 2, Problem 2.41P , additional homework tip  10

In this molecule, both the C-Cl bonds are present above the plane (that is wedge notation). Therefore, the directions of the vectors of dipole moment of both the C-Cl bonds are in the same direction, giving net dipole moment to the molecule.

Conclusion

Dipole moment on this molecule is not symmetrically distributed; hence the given molecule J is polar.

Interpretation Introduction

(k)

Interpretation:

The polarity of the given molecules is to be determined.

Concept introduction:

The dipole moment of a molecule is a measure of the magnitude of its dipole. A dipole moment is a vector, which has both magnitude and direction. Bond polarity originates from bonds between atoms of different electronegativity. Symmetry of molecules also predicts the polarity of a molecule.

Expert Solution
Check Mark

Answer to Problem 2.41P

Molecule K is polar.

Explanation of Solution

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 2, Problem 2.41P , additional homework tip  11

In this molecule, one C-Cl bond is present above the plane (that is, the wedge notation), and another C-Cl bond is present below the plane (that is, the dotted notation). Therefore, the directions of the vectors of dipole moment of both the C-Cl bonds are in opposite direction, which get cancelled out with each other, giving no net dipole moment to the molecule.

Conclusion

Dipole moment on this molecule is symmetrically distributed; hence the given molecule K is nonpolar.

Interpretation Introduction

(l)

Interpretation:

The polarity of the given molecules is to be determined.

Concept introduction:

The dipole moment of a molecule is a measure of the magnitude of its dipole. A dipole moment is a vector, which has both magnitude and direction. Bond polarity originates from bonds between atoms of different electronegativity. Symmetry of molecules also predicts the polarity of a molecule.

Expert Solution
Check Mark

Answer to Problem 2.41P

Molecule L is polar.

Explanation of Solution

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 2, Problem 2.41P , additional homework tip  12

In this molecule, though both the C-Cl bonds are in opposite direction, both the chlorines are present on carbon 1 and 2 respectively. Therefore, there is no symmetry, giving a charge separation and net dipole moment as well to the molecule.

Conclusion

Dipole moment on this molecule is not symmetrically distributed; hence the given molecule L is polar.

Interpretation Introduction

(m)

Interpretation:

The polarity of the given molecules is to be determined.

Concept introduction:

The dipole moment of a molecule is a measure of the magnitude of its dipole. A dipole moment is a vector, which has both magnitude and direction. Bond polarity originates from bonds between atoms of different electronegativity. Symmetry of molecules also predicts the polarity of a molecule.

Expert Solution
Check Mark

Answer to Problem 2.41P

Molecule M is nonpolar.

Explanation of Solution

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 2, Problem 2.41P , additional homework tip  13

In this molecule, two C-Cl bonds are above the plane, and two C-Cl bonds are below the plane; hence the molecule has symmetry. The directions of the vectors of dipole moment of all the four C-Cl bonds are cancelled with each other, giving no net dipole moment to the molecule.

Conclusion

Dipole moment on this molecule is symmetrically distributed; hence the given molecule M is nonpolar.

Interpretation Introduction

(n)

Interpretation:

The polarity of the given molecules is to be determined.

Concept introduction:

The dipole moment of a molecule is a measure of the magnitude of its dipole. A dipole moment is a vector, which has both magnitude and direction. Bond polarity originates from bonds between atoms of different electronegativity. Symmetry of molecules also predicts the polarity of a molecule.

Expert Solution
Check Mark

Answer to Problem 2.41P

Molecule N is polar.

Explanation of Solution

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5, Chapter 2, Problem 2.41P , additional homework tip  14

In this molecule, two C-Cl and two C-Br bonds are present. Since chlorine is more electronegative than bromine, the direction of the vector of dipole moment is towards C-Cl bonds. Therefore, there is a net dipole moment present in this molecule.

Conclusion

Dipole moment on this molecule is not symmetrically distributed; hence the given molecule N is polar.

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Chapter 2 Solutions

ORGANIC CHEMISTRY E-BOOK W/SMARTWORK5

Ch. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.13PCh. 2 - Prob. 2.14PCh. 2 - Prob. 2.15PCh. 2 - Prob. 2.16PCh. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. 2.27PCh. 2 - Prob. 2.28PCh. 2 - Prob. 2.29PCh. 2 - Prob. 2.30PCh. 2 - Prob. 2.31PCh. 2 - Prob. 2.32PCh. 2 - Prob. 2.33PCh. 2 - Prob. 2.34PCh. 2 - Prob. 2.35PCh. 2 - Prob. 2.36PCh. 2 - Prob. 2.37PCh. 2 - Prob. 2.38PCh. 2 - Prob. 2.39PCh. 2 - Prob. 2.40PCh. 2 - Prob. 2.41PCh. 2 - Prob. 2.42PCh. 2 - Prob. 2.43PCh. 2 - Prob. 2.44PCh. 2 - Prob. 2.45PCh. 2 - Prob. 2.46PCh. 2 - Prob. 2.47PCh. 2 - Prob. 2.48PCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.1YTCh. 2 - Prob. 2.2YTCh. 2 - Prob. 2.3YTCh. 2 - Prob. 2.4YTCh. 2 - Prob. 2.5YTCh. 2 - Prob. 2.6YTCh. 2 - Prob. 2.7YTCh. 2 - Prob. 2.8YTCh. 2 - Prob. 2.9YTCh. 2 - Prob. 2.10YTCh. 2 - Prob. 2.11YTCh. 2 - Prob. 2.12YTCh. 2 - Prob. 2.13YTCh. 2 - Prob. 2.14YTCh. 2 - Prob. 2.15YTCh. 2 - Prob. 2.16YTCh. 2 - Prob. 2.17YTCh. 2 - Prob. 2.18YTCh. 2 - Prob. 2.19YTCh. 2 - Prob. 2.20YT
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