Concept explainers
(a)
To determine: The reactions of the given compounds with water.
Interpretation: The reactions of the given compounds with water are to be stated.
Concept introduction: When an acid donates a proton, the species formed is known as conjugate base and when the base accepts a proton, the species formed is known as conjugate acid.
(b)
To determine: The corresponding
Interpretation: The
Concept introduction: The equilibrium constant of an acid dissociation reaction depends on the strength of an acid involved in the reaction. The
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Organic Chemistry (9th Edition)
- The ammonium ion (NH4 +, pKa = 9.25), has a lower pKa than the methylammonium ion (CH3NH3 +, pKa = 10.66) Which is the stronger base, ammonia (NH3) or methylamine (CH3NH2) ? Explainarrow_forwardHow would the pKa values of carboxylicacids, alcohols, ammonium ions 1RNH32 + , phenol, and an anilinium ion 1C6H5NH32 + change if they were determined in a solvent less polar than water?arrow_forwardGiven that the Ka value for acetic acid is 1.8 × 10−5 and the Ka value for hypochlorousacid is 3.5 × 10−8, which is the stronger base, OCl− or C2H3O2−?arrow_forward
- Calculate the pKa of each acid and indicate which is the stronger acid. C6O2H8, Ka = 1.7 x 10–5 C2O4H2, Ka = 5.9 x 10–2arrow_forwardexplain in great detail why the pKa values are what they are and compare them among the three compounds. The conjugate acids that are protonated are drawn in red for each compound. Which one based on the pKa is most acidic and what does that tell you about how basic their lone pairs are?arrow_forwardPhthalic acid and isophthalic acid have protons on two carboxy groupsthat can be removed with base. (a) Explain why the pKa for loss of thefirst proton (pKa1) is lower for phthalic acid than isophthalic acid. (b)Explain why the pKa for loss of the second proton (pKa2) is higher forphthalic acid than isophthalic acid.arrow_forward
- The Ka of acetic acid (CH3CO2H) is 1.8x10-5 and the Kb of methylamine (CH3NH2) is 4.4x10-4. Complete the following equilibrium reaction (acid-base reaction) equation and predict the side of the equilibrium that is favored. Explain. Show all your work.arrow_forwardWhich of the following reactions favor formation of the products? (For the pKa values necessary to solve this problem, see Appendix I. Recall that the equilibrium favors formation of the weaker acidarrow_forwardWhat steps would you need to take to calculate the pKa1 and pKa2 of something? For example: hydrosulfuric acid H2S(aq) (-38.6 ΔH^0 f kJ mol^-1).arrow_forward
- Thiocyanic acid (HSCN) is an inorganic acid (pKa = 1.1 at 25 °C) that can be classified as “strong” largely due to resonance stabilization of its conjugate base, thiocyanate (SCN– ). In the space provided below, draw Lewis electron dot structures of SCN- and all of its important resonance forms.arrow_forwardWhat do you mean by carbon acid? What is the range of their pKa's?arrow_forwardDicarboxylic acids have two dissociation constants, one for the initial dissociation into a monoanion and one for the second dissociation into a dianion. For oxalic acid, HO2C—CO2H, the first ionization constant is pKal = 1.2 and the second ionization constant is pKa2 = 4.2. Why is the second carboxyl group far less acidic than the first?arrow_forward