EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
3rd Edition
ISBN: 9781259298424
Author: SMITH
Publisher: VST
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Question
Chapter 23.3, Problem 23.5P
Interpretation Introduction
Interpretation:
Energy change in the hydrolysis of creatine phosphate to creatine and the phosphorylation of ADP to ATP needs to be calculated. Whether it is energy released or required in this reaction needs to be explained.
Concept Introduction:
Creatine phosphate is a phosphorylated creatine molecule synthesized in the body from the amino acid guanine. Creatine phosphate is an energy storage molecule in muscles that can release high energy and produce ATP.
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Chapter 23 Solutions
EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
Ch. 23.2 - Prob. 23.1PCh. 23.3 - Prob. 23.2PCh. 23.3 - Prob. 23.3PCh. 23.3 - Prob. 23.4PCh. 23.3 - Prob. 23.5PCh. 23.4 - Prob. 23.6PCh. 23.4 - Prob. 23.7PCh. 23.4 - Prob. 23.8PCh. 23.4 - Prob. 23.9PCh. 23.4 - Prob. 23.10P
Ch. 23.5 - Prob. 23.11PCh. 23.5 - Prob. 23.12PCh. 23.5 - Prob. 23.13PCh. 23.6 - Prob. 23.14PCh. 23.6 - Prob. 23.15PCh. 23.6 - Prob. 23.16PCh. 23 - Prob. 23.17PCh. 23 - Prob. 23.18PCh. 23 - Prob. 23.19PCh. 23 - Prob. 23.20PCh. 23 - Prob. 23.21PCh. 23 - Prob. 23.22PCh. 23 - Prob. 23.23PCh. 23 - Prob. 23.24PCh. 23 - Prob. 23.25PCh. 23 - Prob. 23.26PCh. 23 - Prob. 23.27PCh. 23 - Prob. 23.28PCh. 23 - The phosphorylation of glucose with forms glucose...Ch. 23 - Prob. 23.30PCh. 23 - Prob. 23.31PCh. 23 - Prob. 23.32PCh. 23 - Prob. 23.33PCh. 23 - Prob. 23.34PCh. 23 - Prob. 23.35PCh. 23 - Prob. 23.36PCh. 23 - Prob. 23.37PCh. 23 - Classify each substance as an oxidizing agent, a...Ch. 23 - Prob. 23.39PCh. 23 - Prob. 23.40PCh. 23 - Prob. 23.41PCh. 23 - Prob. 23.42PCh. 23 - Prob. 23.43PCh. 23 - Prob. 23.44PCh. 23 - Prob. 23.45PCh. 23 - Prob. 23.46PCh. 23 - Prob. 23.47PCh. 23 - Prob. 23.48PCh. 23 - Prob. 23.49PCh. 23 - Prob. 23.50PCh. 23 - Prob. 23.51PCh. 23 - Prob. 23.52PCh. 23 - Prob. 23.53PCh. 23 - Prob. 23.54PCh. 23 - Prob. 23.55PCh. 23 - Prob. 23.56PCh. 23 - Prob. 23.57PCh. 23 - Prob. 23.58PCh. 23 - Prob. 23.59PCh. 23 - Prob. 23.60PCh. 23 - Prob. 23.61PCh. 23 - Prob. 23.62PCh. 23 - Prob. 23.63PCh. 23 - Prob. 23.64PCh. 23 - Prob. 23.65PCh. 23 - Prob. 23.66PCh. 23 - Prob. 23.67PCh. 23 - Prob. 23.68PCh. 23 - Prob. 23.69PCh. 23 - Prob. 23.70PCh. 23 - Prob. 23.71PCh. 23 - Prob. 23.72PCh. 23 - Prob. 23.73PCh. 23 - Prob. 23.74PCh. 23 - Prob. 23.75CPCh. 23 - Prob. 23.76CP
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- The first step of the metabolic process known as glycolysis is the conversion of glucose to glucose- 6-phosphate. This process has a positive value for rG' Glucose + Pi Glucose-6-phosphate + H2O rG' = +13.8 kJ/mol-rxn This reaction is coupled to the hydrolysis of ATP ATP + H2O ADP + Pi rG' = -30.5 kJ/mol-rxn What is the sum of these two equations and the value of rG' for the coupled reaction? Is the coupled reaction product-favored at equilibrium?arrow_forwardDescribeenergy consumed vs released in reactions. Differentiate between endergonic vs exergonic reactions, anabolism vs catabolism, and coupled reactions.arrow_forwardThe oxidation of 1 mol of glucose supplies enough meta-bolic energy to form 36 mol of ATP. Oxidation of 1 mol of a typ-ical dietary fat like tristearin (C₅₇H₁₁₆O₆) yields enough energyto form 458 mol of ATP. (a) How many molecules of ATP canform per gram of glucose? (b) Per gram of tristearin?arrow_forward
- 1- Find the amount of energy released (in kcal) by: • 1 gram of proteins • 1 gram of carbohydrates • 1 gram of fatsarrow_forwardThe AG" of the dephosphorylation of phosphocreatine is -43.0 kJ/mol. Phosphocreatine → creatine +Pi; -43.0kJ/mol When coupled to the phosphorylation of ADP to ATP (+30.5kJ/mol) ADP +Pi → ATP; +30.5 kJ/mol calculate the actual, physiological AG for the following reaction in kJ/mol: Phosphocreatine + ADP creatine + ATP at 37°C, with concentrations as follows: Phosphocreatine = 0.715 mM creatine = 0.566 mM ADP = 0.431 mM ATP = 2.382 mMarrow_forwardWhich metabolic pathway is directly responsible for the production of the most ATP molecules?arrow_forward
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