Concept explainers
Interpretation: A stepwise mechanism for the given reaction of benzaldehyde
Concept Introduction: Aldol reaction is the condensation reaction of the
The crossed aldol reaction takes place between the two different carbonyl compounds that is between two different
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ORGANIC CHEMISTRY
- β-D-Glucose, a hemiacetal, can be converted to a mixture of acetals on treatment with CH3OH in the presence of acid. Draw a stepwise mechanism for this reaction. Explain why two acetals are formed from a single starting material.arrow_forwardDraw the product when each compound is treated with either (CH3)2CuLi, followed by H2O, or HC≡CLi, followed by H2O.arrow_forwardDraw the products formed when p-methylaniline (p-CH3C6H4NH2) istreated with following reagent. CH3COCl, AlCl3arrow_forward
- Draw the product formed when phenylacetic acid (C6H5CH2COOH) istreated with each reagent. With some reagents, no reaction occurs. NaHCO3arrow_forwardDraw the product formed when phenylacetic acid (C6H5CH2COOH) istreated with following reagent. With some reagents, no reaction occurs. NaOHarrow_forwardDraw 2 enol forms of the following diketone.arrow_forward
- What is the best choice of reagent to perform the following transformation? an ai A) Na₂CrO7 OH ? B) NaOH C) PCC D) HIO4arrow_forwardAspirin is an anti-inflammatory agent because it inhibits the conversion of arachidonic acid to prostaglandins by the transfer of its acetyl group (CH3CO−) to an OH group at the active site of an enzyme. This reaction, called transesterification, results in the conversion of one ester to another by a nucleophilic acyl substitution reaction. Draw a stepwise mechanism for the given transesterification.arrow_forwardAnswer the following question about curcumin, a yellow pigmentisolated from turmeric, a tropical perennial in the ginger family and aprincipal ingredient in curry powder. Most enols, compounds that contain a hydroxy group bonded to a C=C, are unstable and tautomerize to carbonyl groups. Draw the keto form of the enol of curcumin, and explain why the enol is more stable than many other enols.arrow_forward
- Draw the products formed when each compound is treated with HNO3 and H2SO4.State whether the reaction occurs faster or slower than a similar reaction with benzene.arrow_forward1. Draw the product formed when phenylacetaldehyde (C6H5CH2CHO) is treated with each reagent:arrow_forwardAnswer the following questions about curcumin, a yellow pigment isolated from turmeric, a tropical perennial in the ginger family and a principal ingredient in curry powder.a.In Chapter 11, we learned that most enols, compounds that contain a hydroxy group bonded to a C=C, are unstable and tautomerize to carbonyl groups. Draw the keto form of the enol of curcumin, and explain why the enol is more stable than many other enols. b.Explain why the enol O—H proton is more acidic than an alcohol O—H proton. c. Why is curcumin colored? d.Explain why curcumin is an antioxidant.arrow_forward
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