EBK FUNDAMENTALS OF GENERAL, ORGANIC, A
8th Edition
ISBN: 8220102895805
Author: Peterson
Publisher: PEARSON
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Chapter 26, Problem 26.45AP
Interpretation Introduction
Interpretation:
Percentage of C and T that expect in sea urchin DNA has to be predicted.
Concept Introduction:
Base pairing in DNA: The two strands of the DNA double helix run in the opposite directions- one in 5’ to 3’ direction and other from 3’ to 5’ direction. The hydrogen bonding between two strands enhances the stability of the DNA; where the alignment of hydrophobic nitrogenous bases in the interior and hydrophilic phosphate and sugar groups on the exterior also enhance the stability. Adenine and thymine gives a pair forming two hydrogen bonds and cytosine and guanine gives rise to another pair forming three hydrogen bonds.
Chargaff’s rule: The amount of adenine and thymine were always equal, and the amount of cytosine and guanine are always equal (A=T and G=C). The proportions of each (A/T: G/C) vary from one species to another.
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Chapter 26 Solutions
EBK FUNDAMENTALS OF GENERAL, ORGANIC, A
Ch. 26.2 - Name the nucleoside shown here. Copy the...Ch. 26.2 - Prob. 26.2PCh. 26.2 - Draw the structure of 2-deoxyadenosine...Ch. 26.2 - Prob. 26.4PCh. 26.2 - Prob. 26.5PCh. 26.3 - Prob. 26.6PCh. 26.3 - Prob. 26.7PCh. 26.4 - Prob. 26.8PCh. 26.4 - Draw the structures of adenine and uracil (which...Ch. 26.4 - Prob. 26.10P
Ch. 26.4 - Prob. 26.11KCPCh. 26.6 - What are Okazaki fragments? What role do they...Ch. 26.6 - Prob. 26.13PCh. 26.8 - Prob. 26.14PCh. 26.8 - Prob. 26.15PCh. 26.9 - Prob. 26.1CIAPCh. 26.9 - Prob. 26.2CIAPCh. 26.9 - Using a variety of sources, research which...Ch. 26.9 - Prob. 26.4CIAPCh. 26.9 - List possible codon sequences for the following...Ch. 26.9 - Prob. 26.17PCh. 26.9 - What amino acids do the following sequences code...Ch. 26.9 - Prob. 26.19PCh. 26.10 - Prob. 26.20PCh. 26.10 - What anticodon sequences of tRNAs match the mRNA...Ch. 26 - Combine the following structures to create a...Ch. 26 - Prob. 26.23UKCCh. 26 - Copy the following simplified drawing of a DNA...Ch. 26 - Prob. 26.25UKCCh. 26 - Prob. 26.26UKCCh. 26 - Prob. 26.27APCh. 26 - Prob. 26.28APCh. 26 - Prob. 26.29APCh. 26 - Prob. 26.30APCh. 26 - Prob. 26.31APCh. 26 - For the following molecule: (a) Label the three...Ch. 26 - Prob. 26.33APCh. 26 - Prob. 26.34APCh. 26 - Prob. 26.35APCh. 26 - Prob. 26.36APCh. 26 - Draw structures to show how the sugar and...Ch. 26 - What is the difference between the 3 end and the 5...Ch. 26 - Prob. 26.39APCh. 26 - Prob. 26.40APCh. 26 - Draw the complete structure of the RNA...Ch. 26 - Prob. 26.42APCh. 26 - Prob. 26.43APCh. 26 - Prob. 26.44APCh. 26 - Prob. 26.45APCh. 26 - If a double-stranded DNA molecule is 22% G, what...Ch. 26 - How are replication, transcription, and...Ch. 26 - Why is more than one replication fork needed when...Ch. 26 - Prob. 26.49APCh. 26 - What are the three main kinds of RNA, and what are...Ch. 26 - Prob. 26.51APCh. 26 - Prob. 26.52APCh. 26 - Prob. 26.53APCh. 26 - Prob. 26.54APCh. 26 - What is a codon and on what kind of nucleic acid...Ch. 26 - Prob. 26.56APCh. 26 - Prob. 26.57APCh. 26 - Prob. 26.58APCh. 26 - What amino acids are specified by the following...Ch. 26 - Prob. 26.60APCh. 26 - What anticodon sequences are complementary to the...Ch. 26 - Prob. 26.62APCh. 26 - Refer to Problem 26.62. What sequence appears on...Ch. 26 - Refer to Problems 26.62 and 26.63. What dipeptide...Ch. 26 - Prob. 26.65APCh. 26 - Prob. 26.66APCh. 26 - Prob. 26.67APCh. 26 - Prob. 26.68APCh. 26 - Prob. 26.69APCh. 26 - Prob. 26.70CPCh. 26 - Prob. 26.71CPCh. 26 - Prob. 26.73CPCh. 26 - Prob. 26.75GPCh. 26 - Prob. 26.76GPCh. 26 - Prob. 26.77GPCh. 26 - Prob. 26.78GP
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- The Bacteria Escherichia coli DNA genome has a molecular mass of about 3.1 X 10° D. In your answers, show how you came up to each result? (a) How many base pairs does this bacterium contain? (b) How many full double-helical turns does this DNA contain? (c) How long is this DNA in µm?arrow_forwardOn the planet Rama, the DNA is of six nucleotide types: A, B, C, D, E, and F. Types A and B are called marzines, C and D are orsines, and E and F are pirines. The following rules are valid in all Raman DNAs: Total marzines = total orsines = total pirines A = C = E B = D = Fa. Prepare a model for the structure of Raman DNA. b. On Rama, mitosis produces three daughter cells. Bearing this fact in mind, propose a replication pattern for your DNA model. c. Consider the process of meiosis on Rama. What comments or conclusions can you suggest?arrow_forwardThe amount of G plus C in an organism’s DNA is 64% of the total base content of that DNA. What are the percentages of A, T, G, and C?arrow_forward
- How do these ratios compare with the (A + G)/(T + C) ratio found in DNA? Explain.arrow_forwardA circular, double-stranded DNA contains 2100 base pairs. The solution conditions are such that DNA has 10.5 bp/turn. (a) What is Lo for this DNA? (b) The DNA is found to have 12 left-handed superhelical turns. What is the superhelix density o?arrow_forwardThe figure shows that the average distance between base pairs measured parallel to the axis of a DNA molecule is 3.4 Å. The average molar mass of a pair of nucleotides is 650 g•mol-1. Estimate the length in cm of a DNA molecule of molar mass 5.1x109 4.0 .26 g•mol-1. cm Roughly how many base pairs are contained in this molecule? [4.0 784615 x base pairs CG G C OH TA Thymine Adenine H. H. OH CH2 N-H.......O CH3 H H N……·H–N HLH TA OH 0-P H2C CG G C H. CH2 Guanine H OH Cytosine ... H-N TA AT H' N.....H-N HLH N-H.......O H2C OH H -o. -P3D0 TA 0- OH H. -CH2 (b) The most common structure of DNA, which is a right-handed double helix. The two strands are held together by hydrogen bonds (a) Base-pair formation between adenine (A) and thymine (T) and between cytosine (C) and guanine (G). and other intermolecular forces.arrow_forward
- The Bacteria Escherichia coli DNA genome has a molecular mass of about 3.1 X 10 9 D. In your answers, show how you came up to each result?(a) How many base pairs does this bacterium contain? (b) How many full double-helical turns does this DNA contain? (c) How long is this DNA in micrometer?arrow_forwardOne gram of cultured human cells contains about 10^9 cells and occupies roughly 1 mL. if the average molecular mass of a base is 660 daltons and each cell contains 6,4 *10^9 bp, what mass of DNA is present in this one-gram sample? If all the DNA molecules in the sample were laid end to end to form a single thread. Would it be long enough to reach from the Earth to the Moon (385.000 kilometers).arrow_forwardOne gram of cultured human cells contains about 109 cells and occupies roughly 1 mL. If the average molecular mass of a base pair is 660 daltons and each cell contains 6.4 x 109 bp, what mass of DNA is present in this one-gram sample? If all the DNA molecules in the sample were laid end to end to form a single thread, would it be long enough to reach from the Earth to the Moon (385,000 kilometers)?arrow_forward
- In sea urchin DNA, which is double stranded, 17.5percent of the bases were shown to be cytosine (C). Whatpercentages of the other three bases are expected to bepresent in this DNA?arrow_forwardDNA structure depends on base pairing of its four nucleotides, A, C, T, and G. Nucleotide A pairs with T, and nucleotide C pairs with G. This forms a four-letter DNA “alphabet." Because DNA codes for amino acids in sets of three nucleotides, there are 4 cubed (4'), or 64, possible combinations, coding for 20 different amino acids. What is the best explanation for why there is no selective advantage for DNA to have five nucleotides (e.g., A, C, T, G, and E) with C pairing with either G or functionally equivalent E? It would be impossible to form the DNA molecule, because it must have an equal number of Cs and Gs. Because G and E have the same role, there would still be four functional letters of the alphabet. Replication would be inaccurate because sometimes C would bond with G and sometimes C would bond with E. There would be a five-letter alphabet with 125 combinations, which is too numerous. It is impossible because there are not five known nucleotides in the cell.arrow_forwardA typical bacterial DNA has a molar mass of 4 × 109 g m ol-1 . Approximately how many nucleotides does itcontain?arrow_forward
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