Essentials of Genetics
9th Edition
ISBN: 9781292108933
Author: KLUG
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 3, Problem 11PDQ
When working out genetics problems in this and succeeding chapters, always assume that members of the P1 generation are homozygous, unless the information or data you are given require you to do otherwise.
Distinguish between homozygosity and heterozygosity.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Unpacking the Problem 44John and Martha are contemplating having children, butJohn’s brother has galactosemia (an autosomal recessivedisease) and Martha’s great-grandmother also had galactosemia. Martha has a sister who has three children, none ofwhom have galactosemia. What is the probability that Johnand Martha’s first child will have galactosemia?1. Can the problem be restated as a pedigree? If so, writeone.2. Can parts of the problem be restated by using Punnettsquares?3. Can parts of the problem be restated by using branchdiagrams?4. In the pedigree, identify a mating that illustratesMendel’s first law.5. Define all the scientific terms in the problem, and lookup any other terms about which you are uncertain.6. What assumptions need to be made in answering thisproblem?7. Which unmentioned family members must be considered? Why?8. What statistical rules might be relevant, and in whatsituations can they be applied? Do such situations existin this problem?9. What are two generalities…
Solving complex genetic problems with the rules of probability (3 traits)
1. Calculate the probability of getting an offspring of pea plant with the genotype, PpyyRr, when crossing PpYyRr and ppyyrr. Show your work.
2. States the phenotypes of the parents and offspring.
Autosomal Recessive Problem: What is probability of individual 2 III in pedigree 1 and individual 1 III in pedigree 2 to have an affect child?
Chapter 3 Solutions
Essentials of Genetics
Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 - CASE STUDY | To test or not to test Thomas first...Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...
Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - Prob. 26PDQCh. 3 -
When working out genetics problems in this and...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Hello, I need help answering number 40(INCLUDING SUB-PARTS) multiple choice questions. Pls and thank you! 40. A.) If all current mitochondrial DNA sequences in humans coalesce to one dated to 70,000 years ago, then: a) this mitochondrial Eve was the only female living 70,000 ago b) this mitochondrial DNA lineage is the only one persisting to the present time c) this mitochondrial Eve can be matched to a single male who lived 70,000 years ago (Y-chromosome Adam) d) mitochondrial DNA diversity 70,000 years ago was definitely higher than that present now B.) If the climate is warming faster than at any time in the last 800,000 years or more, then: a) strong directional selection for adaptations that allow survival and reproduction in a warmer world will be present b) sufficient additive genetic variance will be present to allow rapid adaptation to a warmer world c) mutation rates will increase to cause more adaptive mutations d) mutation rates will decrease due to the effect of heat on…arrow_forwardMultiple choices: Question: Handedness (whether you are right or left-handed) shows a 79% concordance in monozygotic twins and a 77% concordance in dizygotic twins. Using this information, do you expect handedness to have a large genetic influence? a. No, although the concordance numbers are high, they are similar between MZ and DZ twins b. No, concordance is not 100%arrow_forwardInstruction: Solve for the genetic problems. a. Genotype of the parentsb. Phenotype of the parentsc. Punnett squared. Genotypic ratioe. Phenotypic ratio Question: Two individuals with widow’s peaks want to have a child with a continuous hairline. Is this possible?arrow_forward
- Question: This is a normal 3 point test cross, except that instead of regular phenotypes, you are looking at DNA markers on a gel. One parent, according to the gel, is heterozygous at each marker. The other parent is homozygous for each marker. (Again, this means it is a test cross: AaEeHh x AAEEHH --but don't be confused by that, because these are not "dominant" and "recessive" per se; the phenotype is just a band on a gel). For each offspring, figure out its genotype (homozygous or heterozygous for each gene. Then, figure that one parent made only AEH gametes, so you can cross that out if it helps.) Then treat it pretty much the same as a 3 point test cross.arrow_forwardGenetics Problem: "Which of the following is typically associated with an autosomal recessive pattern of inheritance?" a. an affected offspring has one or more affected parents b. two affected heterozygous individuals will have 25% of their offspring unaffected c. an affected offspring has two unaffected parents d. an affected individual with one affected parent will have 50% of its offspring affectedarrow_forwardQuestion: Suppose the progeny were crossed. Fill in the Punnett Squares below and answer the following questions. Seed Color Seed Shape R r A a In a pea plant experiment, the allele (R) producing yellow seed color is dominant, and the allele (r) producing green seed color is recessive. A homozygous recessive genotype would produce green seeds. Similarly, the allele (A) producing round seed shape is dominant to the allele (a) that produces wrinkled seed shape. A homozygous recessive genotype would produce wrinkled seeds. Both traits sort independently of each other. Given a pure-breeding cross between a round, green pea plant and a wrinkled yellow plant, complete the rest of the Punnett Squares below, and answer the following questions. R R A A RA Ra Ra raarrow_forward
- Unpacking Problem 731. Define homozygous, mutation, allele, closely linked, recessive, wild type, crossing over, nondisjunction, testcross, phenotype, and genotype.2. Does this problem concern sex linkage? Explain.3. How many chromosomes does Drosophila have?4. Draw a clear pedigree summarizing the results of crosses1, 2, and 3.5. Draw the gametes produced by both parents in cross 1.6. Draw the chromosome 4 constitution of the progeny ofcross 1.7. Is it surprising that the progeny of cross 1 are wild-typephenotype? What does this outcome tell you?8. Draw the chromosome 4 constitution of the male testerused in cross 2 and the gametes that he can produce.9. With respect to chromosome 4, what gametes can thefemale parent in cross 2 produce in the absence of nondisjunction? Which would be common and which rare?10. Draw first- and second-division meiotic nondisjunctionin the female parent of cross 2, as well as in the resultinggametes.11. Are any of the gametes from part 10 aneuploid?12.…arrow_forwardNeed help with Punnet Squares. 1.pku is an auto recessive disorder that can ultimately lead to brain damage. People who are heterozygous are healthy even though they carry the alle. If a women is a heterozygous carrier and a man who has the trait has a child, what are the chances that teh child would have PKU? what is the inheritance pattern?arrow_forwardI need help solving this : In humans, the X chromosome is large in comparison to the Y chromosome. The X chromosome carries information for many traits that aren't related to the sex of the individual. Alleles carried only by the X chromosome are said to be X-linked (or some-times, sex-linked). Some of the alleles on the tiny Y chromosome appear to have no counterparts on X. These Y-linked alleles code for traits that are found only in males. Among the X-linked traits are a number of recessive genetic disorders. One of these is hemophilia, the inability to produce proteins necessary for blood clotting. Hemophiliacs can bleed to death from relatively minor cuts or bruises. Historical records dating back thousands of years mention the inheritance pattern of hemophilia. Among the ancient Hebrews, sons born to women with a family history of hemophilia were excused from circumcision. Hemophilia was common during the 1800s in the royal families of Europe, whose members often intermarried.…arrow_forward
- Keeping it in the family!”- How do you think consanguinity is increasing the risk factors of genetic disorders? Explain with examples (at least two). It won’t be possible to change the tradition all of a sudden. If you are a clinical geneticist, how you will be managing this type of community?arrow_forwardpls dont copy existing answers or i will dislike your answer thanks Phenylketonuria (PKU) is a disorder caused by a recessive allele. Two carrier individuals have progeny. Answer the following questions in order and show solutions whenever relevant. 1. If they have a normal child, what is the probability that he or she will be heterozygous? 2. If they have three children, what is the probability of having 2 affected children and one normal child?arrow_forwardI need help finding the correct answers. the formula I used is % idenity=(length of the aligned region- the number of mismatches)/length of the aligned regionx100 for sequnce `1 and 3 I got a 70 percent idenity and 3 mismatches I think I am counting the wrong mismatches? can someone correct my answers and show me how they got theres and do not use cheggarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
How to solve genetics probability problems; Author: Shomu's Biology;https://www.youtube.com/watch?v=R0yjfb1ooUs;License: Standard YouTube License, CC-BY
Beyond Mendelian Genetics: Complex Patterns of Inheritance; Author: Professor Dave Explains;https://www.youtube.com/watch?v=-EmvmBuK-B8;License: Standard YouTube License, CC-BY