the percent of the students spent between $215 and $395 on text-books that quarter.

Question

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Answer 1

Question

Chapter 3, Problem 3.47RE

(a)

To determine

To Calculate: the percent of the students spent between $215 and $395 on text-books that quarter.

(a)

Expert Solution

Answer to Problem 3.47RE

68%

Explanation of Solution

The student spent between $215 and $395 is one standard deviation below and above the mean. This is 68% of the students are between $215 and $395.

(b)

To determine

To Calculate: the standard score her and percent of the students spent less than she did on textbooks that quarter.

(b)

Expert Solution

Answer to Problem 3.47RE

Z-score = -0.20

42.07%

Explanation of Solution

Given:

x=287μ=305σ=90

Formula used:

z=x−μσ

Calculation:

z=x−μσ=287−30590=−0.20

Raw containing the correct integer 10th of z score (-0.2) and the column containing the corresponding 100th of z score (0.00) so the percent less than the z-score is

0.4207 Or 42.07%

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Answer 2

Question

Chapter 3, Problem 3.47RE

(a)

To determine

To Calculate: the percent of the students spent between $215 and $395 on text-books that quarter.

(a)

Expert Solution

Answer to Problem 3.47RE

68%

Explanation of Solution

The student spent between $215 and $395 is one standard deviation below and above the mean. This is 68% of the students are between $215 and $395.

(b)

To determine

To Calculate: the standard score her and percent of the students spent less than she did on textbooks that quarter.

(b)

Expert Solution

Answer to Problem 3.47RE

Z-score = -0.20

42.07%

Explanation of Solution

Given:

x=287μ=305σ=90

Formula used:

z=x−μσ

Calculation:

z=x−μσ=287−30590=−0.20

Raw containing the correct integer 10th of z score (-0.2) and the column containing the corresponding 100th of z score (0.00) so the percent less than the z-score is

0.4207 Or 42.07%

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 3, Problem 3.47RE

(a)

To determine

To Calculate: the percent of the students spent between $215 and $395 on text-books that quarter.

(a)

Expert Solution

Answer to Problem 3.47RE

68%

Explanation of Solution

The student spent between $215 and $395 is one standard deviation below and above the mean. This is 68% of the students are between $215 and $395.

(b)

To determine

To Calculate: the standard score her and percent of the students spent less than she did on textbooks that quarter.

(b)

Expert Solution

Answer to Problem 3.47RE

Z-score = -0.20

42.07%

Explanation of Solution

Given:

x=287μ=305σ=90

Formula used:

z=x−μσ

Calculation:

z=x−μσ=287−30590=−0.20

Raw containing the correct integer 10th of z score (-0.2) and the column containing the corresponding 100th of z score (0.00) so the percent less than the z-score is

0.4207 Or 42.07%

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 3, Problem 3.47RE

(a)

To determine

To Calculate: the percent of the students spent between $215 and $395 on text-books that quarter.

(a)

Expert Solution

Answer to Problem 3.47RE

68%

Explanation of Solution

The student spent between $215 and $395 is one standard deviation below and above the mean. This is 68% of the students are between $215 and $395.

(b)

To determine

To Calculate: the standard score her and percent of the students spent less than she did on textbooks that quarter.

(b)

Expert Solution

Answer to Problem 3.47RE

Z-score = -0.20

42.07%

Explanation of Solution

Given:

x=287μ=305σ=90

Formula used:

z=x−μσ

Calculation:

z=x−μσ=287−30590=−0.20

Raw containing the correct integer 10th of z score (-0.2) and the column containing the corresponding 100th of z score (0.00) so the percent less than the z-score is

0.4207 Or 42.07%

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 3, Problem 3.47RE

(a)

To determine

To Calculate: the percent of the students spent between $215 and $395 on text-books that quarter.

(a)

Expert Solution

Answer to Problem 3.47RE

68%

Explanation of Solution

The student spent between $215 and $395 is one standard deviation below and above the mean. This is 68% of the students are between $215 and $395.

(b)

To determine

To Calculate: the standard score her and percent of the students spent less than she did on textbooks that quarter.

(b)

Expert Solution

Answer to Problem 3.47RE

Z-score = -0.20

42.07%

Explanation of Solution

Given:

x=287μ=305σ=90

Formula used:

z=x−μσ

Calculation:

z=x−μσ=287−30590=−0.20

Raw containing the correct integer 10th of z score (-0.2) and the column containing the corresponding 100th of z score (0.00) so the percent less than the z-score is

0.4207 Or 42.07%

Answer 6

Chapter 3, Problem 3.47RE

(a)

To determine

To Calculate: the percent of the students spent between $215 and $395 on text-books that quarter.

(a)

Expert Solution

Answer to Problem 3.47RE

68%

Explanation of Solution

The student spent between $215 and $395 is one standard deviation below and above the mean. This is 68% of the students are between $215 and $395.

Answer 7

Chapter 3, Problem 3.47RE

(a)

To determine

To Calculate: the percent of the students spent between $215 and $395 on text-books that quarter.

Answer 8

(a)

Expert Solution

Answer to Problem 3.47RE

68%

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The student spent between $215 and $395 is one standard deviation below and above the mean. This is 68% of the students are between $215 and $395.

Answer 13

(b)

To determine

To Calculate: the standard score her and percent of the students spent less than she did on textbooks that quarter.

(b)

Expert Solution

Answer to Problem 3.47RE

Z-score = -0.20

42.07%

Explanation of Solution

Given:

x=287μ=305σ=90

Formula used:

z=x−μσ

Calculation:

z=x−μσ=287−30590=−0.20

Raw containing the correct integer 10th of z score (-0.2) and the column containing the corresponding 100th of z score (0.00) so the percent less than the z-score is

0.4207 Or 42.07%

Answer 14

(b)

To determine

To Calculate: the standard score her and percent of the students spent less than she did on textbooks that quarter.

Answer 15

(b)

Expert Solution

Answer to Problem 3.47RE

Z-score = -0.20

42.07%

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Given:

x=287μ=305σ=90

Formula used:

z=x−μσ

Calculation:

z=x−μσ=287−30590=−0.20

Raw containing the correct integer 10th of z score (-0.2) and the column containing the corresponding 100th of z score (0.00) so the percent less than the z-score is

0.4207 Or 42.07%