Genetics: From Genes to Genomes
6th Edition
ISBN: 9781259700903
Author: Leland Hartwell Dr., Michael L. Goldberg Professor Dr., Janice Fischer, Leroy Hood Dr.
Publisher: McGraw-Hill Education
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Textbook Question
Chapter 3, Problem 4P
Recall from Chapter 2 (Fig. 2.20) that Mendel’s R gene specifies an enzyme called Sbe1 that forms branched starches. The dominant allele (R) makes protein, and the recessive allele (r) is nonfunctional. When considering the
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Mendel crossed two Pea plants for plant height and flower color Tall plant (T) is dominant to Short Plant (t). Purple Flower (P) is dominant to white flower (p). Using the following information perform the dihybrid cross using punnett squares that will predict all possible genotypes of the offspring and list the number and description of the phenotypes of the offspring. A. One plant homozygous dominant for plant height and flower color crossed with another plant homozygous recessive for plant height and heterozygous for flower color.
When Gregor Mendel performed his breeding experiments on pea plants, he discovered that tallness in the plants is inherited through a simple dominant trait (coded "T") with shortness as the recessive trait (coded "t"). Imagine that Mendel bred a homozygous dominant pea plant with a pea plant heterozygous for tallness. Draw a Punnett Square to help you answer this question and the next one:
In the 1st generation of offspring, we expect the phenotypes (for tallness) to include…
a) 50% homozygous dominant, 50% heterozygous
b) 100% heterozygous
c) 50% tall, 50% short
d) 100% tall
e) None of the above
When Gregor Mendel performed his breeding experiments on pea plants, he discovered that tallness in the plants is inherited through a simple dominant trait (coded "T") with shortness as the recessive trait (coded "t"). Imagine that Mendel bred a homozygous dominant pea plant with a pea plant heterozygous for tallness. Draw a Punnett Square to help you answer this question and the next one:
In the 1st generation of offspring, we expect the genotypes (for tallness) to include…
a) 50% homozygous dominant, 50% heterozygous
b) 100% heterozygous
c) 50% tall, 50% short
d) 100% tall
e) None of the above
Chapter 3 Solutions
Genetics: From Genes to Genomes
Ch. 3 - For each of the terms in the left column, choose...Ch. 3 - In four-oclocks, the allele for red flowers is...Ch. 3 - The Aa heterozygous snapdragons in Fig. 3.3 are...Ch. 3 - Recall from Chapter 2 Fig. 2.20 that Mendels R...Ch. 3 - In the fruit fly Drosophila melanogaster, very...Ch. 3 - A cross between two plants that both have yellow...Ch. 3 - In radishes, color and shape are each controlled...Ch. 3 - A wild legume with white flowers and long pods is...Ch. 3 - Assuming no involvement of the Bombay phenotype in...Ch. 3 - Several genes in humans in addition to the ABO...
Ch. 3 - Alleles of the gene that determines seed coat...Ch. 3 - One of your fellow students tells you that there...Ch. 3 - In a population of rabbits, you find three...Ch. 3 - In clover plants, the pattern on the leaves is...Ch. 3 - Fruit flies with one allele for curly wings Cy and...Ch. 3 - In certain plant species such as tomatoes and...Ch. 3 - In a species of tropical fish, a colorful orange...Ch. 3 - People heterozygous for normal and nonfunctional...Ch. 3 - Using old Fugate family Bibles and the Perry...Ch. 3 - A rooster with a particular comb morphology called...Ch. 3 - A black mare was crossed to a chestnut stallion...Ch. 3 - Filled-in symbols in the pedigree that follows...Ch. 3 - You perform a cross between two true-breeding...Ch. 3 - a. How would you describe inheritance of flower...Ch. 3 - Suppose the intermediate called Colorless...Ch. 3 - Explain the difference between epistasis and...Ch. 3 - The dominant allele H reduces the number of body...Ch. 3 - Secretors genotypes SS and Ss secrete their A and...Ch. 3 - Normally, wild violets have yellow petals with...Ch. 3 - A woman who is blood type B has a child whose...Ch. 3 - The following table shows the responses of blood...Ch. 3 - Three different pure-breeding strains of corn that...Ch. 3 - In mice, the AY allele of the agouti gene is a...Ch. 3 - A student whose hobby was fishing pulled a very...Ch. 3 - Suppose that blue flower color in a plant species...Ch. 3 - This problem examines possible biochemical...Ch. 3 - Considering your answers to Problem 36, does the...Ch. 3 - You picked up two mice one female and one male...Ch. 3 - Figure 3.21 and Fig. 3.28b both show traits that...Ch. 3 - Three genes in fruit flies affect a particular...Ch. 3 - The garden flower Salpiglossis sinuata painted...Ch. 3 - In foxgloves, three different petal phenotypes...Ch. 3 - In a culture of fruit flies, matings between any...Ch. 3 - Prob. 44PCh. 3 - A couple wants to know the probability that their...Ch. 3 - This problem illustrates why classical geneticists...Ch. 3 - Prob. 47PCh. 3 - Familial hypercholesterolemia FH is an inherited...Ch. 3 - You have come into contact with two unrelated...Ch. 3 - Polycystic kidney disease is a dominant trait that...Ch. 3 - Identical monozygotic twins have similar, but not...Ch. 3 - Using each of the seven coat color genes discussed...
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- The text outlines some of the problems Frederick William I encountered in his attempt to breed tall Potsdam Guards. a. Why were the results he obtained so different from those obtained by Mendel with short and tall pea plants? b. Why were most of the children shorter than their tall parents?arrow_forwardMore Crosses with Pea Plants: The Principle of Independent Assortment Determine the possible genotypes of the following parents by analyzing the phenotypes of their children. In this case, we will assume that brown eyes (B) is dominant to blue (b) and that right-handedness (R) is dominant to left-handedness (r). a. Parents: brown eyes, right-handed brown eyes, right-handed Offspring: 3/4 brown eyes, right-handed 1/4 blue eyes, right-handed b. Parents: brown eyes, right-handed blue eyes, right-handed Offspring: 6/16 blue eyes, right-handed 2/16 blue eyes, left-handed 6/16 brown eyes, right-handed 2/16 brown eyes, left-handed c. Parents: brown eyes, right-handed blue eyes, left-handed Offspring: 1/4 brown eyes, right-handed 1/4 brown eyes, left-handed 1/4 blue eyes, right-handed 1/4 blue eyes, left-handedarrow_forwardMendel's concept of dominance states that in a genotype where two different alleles of a locus are present, only the trait encoded by the dominant allele is observed. Give a molecular explanation for dominance, i.e. explain intracellular molecular events that can result in what we observe as dominance on a phenotypic level. Use the gene that encodes seed shape in peas as an example, where roun(R) is dominant over wrinkled(r), to explain how RR and Rr plants can have the same phenotype.arrow_forward
- In general terms, genes found on the same chromosome are linked, and will appear to defy Mendel’s Law of Independent Assortment. This law states that alleles (Links to an external site.) for different traits (Links to an external site.) are transmitted (Links to an external site.) to offspring (Links to an external site.) independently of one another. Functionally, this means that in a dihybrid testcross, in which a heterozygote is crossed to a double homozygous recessive individual, the expected 1:1:1:1 ratio will not be obtained. Instead, lower than expected numbers of non-parentals will result, because these non-parental flies are the result of recombination during synapsis. Interestingly, and functionally important in this exercise, synapsis only occurs in female fruit flies, requiring that the heterozygote in any study of linkage must be the female. Determining the relative positions of linked genes on a chromosome can be accomplished by calculating the frequency of…arrow_forward. When Mendel crossed a large number of tall pea plants with short pea plants, all F1 plants were tall. The F2 generation was created by self-pollinating the F1 plants. Complete a genetic cross of F2 to show the genotypes and phenotypes of the offspring. State the ratio of phenotypes expected in the F2 offspring. Mendel’s First Law of inheritance states that, “…the alleles of a given locus segregate into separate gametes.” Explain how the genetic diagram above proves this law. (AC 2.1) can i get help please.arrow_forwardWhite fruit color in squash is due to a dominant allele. Yellow fruit occurs in plants which are homozygous for the recessive allele. If pollen from the anthers of a heterozygous white-fruited plant is placed on the pistil of the yellow-fruited plant; show, using ratios, the genotypes and phenotypes you would expect the seeds from this cross to produce. a. Expected genotypic ratio: Expected phenotypic ratio:arrow_forward
- Mendel obtained his initial pea plant varieties from local breeders who were developing new varieties that might be useful or interesting. To generate these new varieties, breeders formed hybrids between existing varieties of different phenotypic characteristics by cross pollination, using techniques they doubtless taught to Mendel. After producing a hybrid, they allowed several generations of self-pollination, as happens naturally if the flowers are not disturbed. a. What if a breeder were working with 7 different, independently segregating genes, as Mendel did? How many generations would it take him to have pure-breeding varieties, starting from an F1 hybrid that is heterozygous for all 7 genes? i. What is the probability that an individual in the F2 generation would be pure-breeding (i.e. is homozygous at all 7 loci)? [Hint: this is an “and” calculation since it must be homozygous at each of the 7 loci. ii. What is the probability that an individual in the F3 generation would…arrow_forwardIn classical Mendelian genetics, how can one check the genotype of a parent (A) expressing the characters of a dominant allele? Select one: a. By performing a back cross with a recessive homozygote parent (B). If the A parent is homozygote for the dominant allele, then all the individuals from the F1 will display the dominant character. If the parent A was, instead, a heterozygote, then 50% of the F1 progeny will express the recessive character (homozygote recessive) and 50% the dominant one (heterozygotes). b. It is impossible to check such genotype without using specific molecular assays. c. By performing a back cross with a dominant homozygote parent (B). If the A parent is homozygote for the dominant allele, then all the individuals from the F1 will display the dominant character.arrow_forwardSuppose that a Mendel's dihybrid cross between two double heterogotes (AaBb x AaBb) gave you the phenotypic ratio of 15:1, assuming that the dominant allele is completely dominant over the recessive allele. Which of the following is CORRECT? A. The A_B_ and aabb have the same phenotype. (_ means either the dominant allele or recessive allele) B. The aaB_ and aabb have the same phenotype. (_ means either the dominant allele or recessive allele) C. The aaB_ and A_bb have the same phenotype. (_ means either the dominant allele or recessive allele) D. All of the above.arrow_forward
- Assume that plant height is determined by a pair of alleles at each of two loci (A and a, B and b) that are additive in their effects. Further assume that each allele represented by an uppercase letter contributes 6 feet to height and that each allele represented by a lowercase letter contributes 2 foot to height. If a plant with genotype Aabb is crossed to a plant with genotype aaBb, what heights are expected in the progeny? 1/216ft : 1/2 12ft 1/4 16ft : 1/2 12ft : 1/4 8ft 1/4 20ft : 1/2 16ft : 1/4 12ft 1/4 24ft : 1/2 20ft : 1/4 16ft 1/2 20ft : 1/2 16ftarrow_forwardThe shape of a pumpkin is determined by the action of two genes A and B. The recessive forms of these two alleles produces a flattened-shaped fruit, whereas the dominant forms of these two alleles produce the typical pumpkin with ridges. When both alleles are heterozygous a disc-shaped pumpkin is produced. If the genotype of the pumpkin plant is homozygous dominant at one allele and heterozygous at the other, the pumpkin will be ball-shaped. If the pumpkin plant is homozygous recessive at one allele and heterozygous at the other allele it produces an oblong-shaped fruit. Plants with genotypes other than the ones listed in this question do not produce pumpkins. Do the following cross: two pumpkin plants capable of making disc-shaped pumpkins are crossed with each other. Based on this cross, answer the following: (Show your work below.) How many of the progeny will make ball-shaped pumpkins?__________________________________________ How many of the progeny will make disc-shaped…arrow_forwardAssume that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. Further assume that each allele represented by an uppercase letter contributes 4 g to weight and that each allele represented by a lowercase letter contributes 1 g to weight. a. If a plant with genotype AA BB is crossed with a plant with genotype aa bb, what weights are expected in the F1 progeny? b. What is the distribution of weight expected in the F2 progeny?arrow_forward
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