BIOCHEMISTRY (LOOSELEAF)-W/ACCESS
9th Edition
ISBN: 9781319425784
Author: BERG
Publisher: Macmillan Higher Education
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Chapter 30, Problem 17P
Interpretation Introduction
Interpretation:
The probable mechanism for the reduction of the transcription rate of a gene by the negative supercoiling should be determined.
Concept introduction:
RNA synthesis (transcription) is the synthesis of an RNA molecule from the nucleotide’s adenine, cytosine, guanine, or uracil. The
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Plz answer ASAP. I will thumb up
You are studying the regulation of the lactose operon in Escherichia coli, by measuring expression of the lacZ gene (i.e production of beta-galactosidase).(a) You identify several loss-of-function mutations in which lacZ is never expressed, in the presence and absence of glucose and lactose. What components of the lac operon could be mutated to produce this phenotype? List all possibilities.
I am more confused. how about we start from begining, you post answers on here, and then we go from there?
1. Identify the open reading frame in the following DNA sequence, the protein that this gene encodes for, its function, and the source.
2. "Look carefully at the DNA sequence and identify the start site for transcription"
3.
Click on the DNA sequence from the start site of transcription, select all of the sequence, and copy the sequence.
Go to the National Center for Biotechnology Information (NCBI) website http://www.ncbi.nlm.nih.gov/. Click on BLAST on the right-hand side under “Popular Resources.” BLAST is a program that will allow you to find the protein sequence for the DNA sequence (gene) you submit. Next click on blastx (translated nucleotide protein).
Paste the DNA sequence into the box under “Entry Query Sequence.” Scroll down and click BLAST. The search may take a few seconds; the page will keep updating until the search is completed. You do not need to enter any…
Chapter 30 Solutions
BIOCHEMISTRY (LOOSELEAF)-W/ACCESS
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- E32. In the technique of DNase I footprinting, the binding of a protein to a region of DNA protects that region from digestion by DNase I by blocking the ability of DNase I to gain access to the DNA. In the DNase I footprinting experiment shown here, a researcher began with a sample of cloned DNA 400 bp in length. This DNA contained a eukaryotic promoter for RNA polymerase II. The assembly of general transcription factors and RNA polymerase II at the core promoter is described in Chapter 12 (see Figure 12.14). For the sample loaded in lane 1, no proteins were added. For the sample loaded in lane 2, the 400-bp fragment was mixed with RNA polymerase II plus TFIID and TFIIB. 2 400 350 250 175 50 Which region of this 400-bp fragment of DNA is bound by RNA polymerase II and TFIID and TFIIB? || III ||| | ||||arrow_forwardPolymerase inhibition. Cordycepin inhibits poly(A) synthesis at low concentrations and RNA synthesis at higher concentrations. NH2 H. он Cordycepin (3'-deoxyadenosine) a. What is the basis of inhibition by cordycepin? b. Why is poly(A) synthesis more sensitive than the synthesis of other RNAS to the presence of cordycepin? c. Does cordycepin need to be modified to exert its effect?arrow_forwardBroken operators. Consider a hypothetical mutation in OR2OR 2 that blocks both A repressor and Cro binding. How would this mutation affect the likelihood of bacteriophage entering the lytic phase?arrow_forward
- RNA transcription reach low error rate under non-equilibrium steady state, what is the energy source to drive transcription ?arrow_forwardAn extra piece. In one type of mutation leading to a form of thalassemia, the mutation of a single base (G to A) generates a new 3' 3' splice site (blue in the illustration below) akin to the normal one (yellow) but farther upstream. Normal 3' end of intron 5' CCTATTGGTCTATTITCCACCCITAGGCTGCTG 3' 5' CCTATTAGTCTAIIIICCACCCTTAGGCTGCTG 3' What is the amino acid sequence of the extra segment of protein synthesized in a thalassemic patient having a mutation leading to aberrant splicing? The reading frame after the splice site begins with TCT.arrow_forwardTranscriptional regulation You are interested in studying the transcriptional regulation of Glp1 promoter. This gene contains a binding site for two proteins A and B. Proteins A and B cannot bind to the DNA at the same time due to steric interference caused by a slight overlap in their binding sites. The binding sites of protein A and protein B can be seen in the figure below. Protein A binds to Site C and Protein B binds to site D. To assess whether either A or B have an influence on Glp1 expression, you create mutations in the DNA that selectively remove the non-overlapping sequences of binding site C or binding site D. You then examine Glp1 mRNA production within adult liver cells. You receive the following data. Experiment number Binding site C Binding site D Glp1 mRNA levels 1 + + high 2 + - high 3 - + none 4 - - none += binding site present, -= binding site absent What does this data tell us about which protein is…arrow_forward
- Part I. Structure-Function Relationships in Genes 1. Consider the "two-line model" of a gene shown below - each line represents one strand of a DNA double helix, and the transcription start site is indicated as +1. Use the two-line models provided when answering the following questions. 3' 5' +1 Assume that you know RNA polymerase will move to the right during transcription. On the diagram above, do the following: • Label "upstream" and "downstream" on this gene • Label where you would find the promoter min I • Draw a box where you would expect to find the TATA box • Draw a third line below the model representing the RNA transcript (label the ends!) • Label one of the DNA strands as the template strand 3' 2. Now, let's try that again! This time assume that you know RNA polymerase will move to the left during transcription. Repeat the same tasks as before on the diagram below: 5' 5' 3' +1 I I 5' 3'arrow_forwardHow many sites? A researcher has isolated a restriction endonuclease that cleaves at only one particular 10-base-pair site. Would this enzyme be useful in protecting cells from viral infections, given that a typical viral genome is 50,000 base pairs long? Explainarrow_forwardRegulation of Genes and Their products 1. Given the following genotypes, explain how the mutation (identified by a (-) superscript) wil affect E. coll grown in lactose medium. Will the lac operon be on or off? Will there be a complete set of gene products from the lac operon? What will be the implication of the missing gene product, if ever? Will the cell be able to survive in the lactose medium or not? a. I+p+o+z- y+ b. i- p+o+z+y+ c. i+p+o- z+y+ d. i+p- o+z+y+ 2. In terms of the trp operon, differentiate between two normal bacterial cultures, one grown in a medium supplied with tryptophan and the other medium without tryptophan. 3. Experiments show that mutations at gene E lead to non-repressible transcription of trp genes. Why?arrow_forward
- . Why is a nonsense suppressor tRNATyr, even though ithas a mutant anticodon that cannot recognize a tyrosinecodon, charged with tyrosine by Tyr tRNA synthetase?arrow_forwardAnswer as Directed. Below is the model of a lac operon. lac I lac Z с promoter operator +1 lac Y lac A DNA 1. In the absence of lactose and the presence of glucose in the bacterial growth media, what proteins are bound to the lac control region? Is the operon being transcribed then? 2. In the presence of lactose and the presence of glucose in the bacterial growth media, what proteins are bound to the lac regulatory region? Is the operon being transcribed then? 3. In the presence of lactose and the absence of glucose in the bacterial growth media, what proteins are bound to the lac control region? 4. Why is it adaptive for a bacterium to not express the genes that encode for that lactose utilization proteins when lactose is not available or when glucose is present? 5. Why is it adaptive for the structural genes for using lactose to be under the control of a single promoter, i.e., synthesize a polycistronic message rather than three monocistronic message?arrow_forwardLike the lac operon, the hexose operon is controlled by a separate regulatory protein under the control of its own promoter (see the schematic of the operon below). The hexose regulatory protein is sensitive to fatty acyl CoA levels. When all hexose fuel sources are depleted, the bacteria switch to lipid metabolism and fatty acyl CoA levels increase. This turns expression of the hexose operon off. +1 +1 Regulatory Gene Pregulator Hexose Operon Genes operon regulator promoter operon promoter 5e. The regulatory protein that controls expression of the hexose operons is a transcriptional ACTIVTOR or REPRESSOR (circle one).arrow_forward
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